如何在React Native中不使用'this'关键字的情况下访问元素的属性?我有一个将父类本身绑定为“ this”的函数,但我想访问被单击元素的属性。这是代码-
import {Circle} from 'react-native-svg';
export default App extends Component {
constructor(props) {
super(props);
this.state = {activeX: null}
}
handleTouch(event) {
const x = event.target.cx; //How to access "cx" property here?
this.setState({ activeX: x });
}
render() {
return (
<Circle cx='10' cy='10' r='5' onPress={this.handleTouch.bind(this)}/>
<Circle cx='20' cy='20' r='5' onPress={this.handleTouch.bind(this)}/>
);
}
}
import ReactNativeComponentTree from'react-native/Libraries/Renderer/src/renderers/native/ReactNativeComponentTree';
并以以下方式访问属性:
const x = ReactNativeComponentTree.getInstanceFromNode(event.currentTarget)._currentElement.props.cx;
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我来说两句