如何初始化变量

肯图姆塔

你好我想构建一个程序，从给定的两个数字中找到偶数和奇数。当我构建它时，它说成功，但它仍然说警告 C4700：使用了未初始化的局部变量“编号”

当我调试它时出现调试错误如何解决这个问题？谁能告诉我它发生的原因？太感谢了

下面是代码

#include<stdio.h>
#include <iostream>
using namespace std;


int main(){

    int number;
    int firstNum,secondNum;

    cout << "Enter the first number: ";
    cin >> firstNum;

   cout << "Enter the second number: ";
    cin >> secondNum;


    if(number % 2 !=0){
    for(number = firstNum;number <= secondNum; number++)
      cout << number<< " ";

    cout << "Odd numbers in given range are: ";
    cout << number<< " ";
    }
    else if(number % 2 ==0){

   for(number = firstNum;number <= secondNum; number++)
     printf("\nEven numbers in given range are: ");

             cout << number << " ";
    }
    return 0;
}

阿布舍克·巴盖特

你的程序出错的原因是你没有初始化你的变量number。我已经纠正了这一点。还有一些其他错误会导致错误输出。我已经更正并重新格式化了您的代码 -

#include<stdio.h>
#include <iostream>
using namespace std;


int main(){

    int number;
    int firstNum,secondNum;

    cout << "Enter the first number: ";
    cin >> firstNum;

   cout << "Enter the second number: ";
    cin >> secondNum;

    number=firstNum;
    for(number = firstNum;number <= secondNum; number++)
      cout << number<< " ";
    //Following piece will print out all odd numbers
    cout << "\nOdd numbers in given range are: ";
    for(number = firstNum;number <= secondNum ; number++)
        if(number&1)
            cout<<number<<" ";
    cout<<"\n";    
    //Following piece will print out all even numbers        
    cout << "Even numbers in given range are: ";
    for(number = firstNum;number <= secondNum ; number++)
        if(!(number&1))
            cout<<number<<" ";
    cout<<"\n";




    return 0;
}

您可能正在尝试打印给定范围内的奇数和偶数。上面的程序正是这样做的。

希望这能解决您的问题！

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