在简单的Shapeless HLIST上进行模式匹配

知道不多

我使用无形库编写了此简单代码

import shapeless.LabelledGeneric
case class Icecream(name: String, numberOfCherries: Int, inCone: Boolean)

object ShapelessRecordEx2 extends App {
   val gen = LabelledGeneric[Icecream]
   val hlist = gen.to(Icecream("vanilla", 2, false))
   hlist match {
      case h :: _ => println(h)
   }
}

但甚至不编译

Error:(12, 14) constructor cannot be instantiated to expected type;
 found   : scala.collection.immutable.::[B]
 required: shapeless.::[String with shapeless.labelled.KeyTag[Symbol with shapeless.tag.Tagged[String("name")],String],shapeless.::[Int with shapeless.labelled.KeyTag[Symbol with shapeless.tag.Tagged[String("numberOfCherries")],Int],shapeless.::[Boolean with shapeless.labelled.KeyTag[Symbol with shapeless.tag.Tagged[String("inCone")],Boolean],shapeless.HNil]]]
      case h :: _ => println(h)

如果我使用普通列表，则此代码会很好。

黄素

您只需要导入，默认情况下scala.Predef就是::从中导入运算符scala.collection.immutable.List。

import shapeless.LabelledGeneric
import shapeless.::
case class Icecream(name: String, numberOfCherries: Int, inCone: Boolean)

object ShapelessRecordEx2 extends App {
   val gen = LabelledGeneric[Icecream]
   val hlist = gen.to(Icecream("vanilla", 2, false))
   hlist match {
      case h :: _ => println(h)
   }
}

还有另一种选择import ListCompat._。

import shapeless.HList.ListCompat._

object ShapelessRecordEx2 extends App {
  val gen = LabelledGeneric[Icecream]
  val hlist = gen.to(Icecream("vanilla", 2, false))
  hlist match {
    case h #: _ => println(h)
  }
}

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