我写了一个代码,它使用BeautifulSoup
一个预先设计的库CommonRegex从网页中抓取联系信息,它基本上是正则表达式来抓取美国地址信息。虽然我能够提取列表形式的信息并将其转换为熊猫数据帧,我无法保存列表中存在的所有值。这是我写的代码:
import pandas as pd
from commonregex import CommonRegex
from urllib.request import urlopen
from bs4 import BeautifulSoup
url = 'https://www.thetaxshopinc.com/pages/contact-tax-accountant-brampton'
html = urlopen(url)
soup = BeautifulSoup(html, 'lxml')
for link in soup.find_all('p'):
df = CommonRegex()
df1 = df.street_addresses(link.get_text())
df2 = df.phones(link.get_text())
df3 = df.emails(link.get_text())
for i in df1:
dfr = pd.DataFrame([i], columns = ['Address'])
for j in df2:
dfr1 = pd.DataFrame([j], columns = ['Phone_no'])
dfr1['Phone_no'] = dfr1['Phone_no'].str.cat(sep=', ')
dfr1.drop_duplicate(inplace = True)
for k in df3:
dfr2 = pd.DataFrame([k], columns = ['Email'])
dfc = pd.concat([dfr, dfr1, dfr2], axis = 1)
这是我得到的结果:-
但是,由于正则表达式为 提取 3 个值Phone no
,即,
我不知道如何解决这个问题,如果你们能帮助我就太好了。
这应该做:
import pandas as pd
from commonregex import CommonRegex
from urllib.request import urlopen
from bs4 import BeautifulSoup
url = 'https://www.thetaxshopinc.com/pages/contact-tax-accountant-brampton'
html = urlopen(url)
soup = BeautifulSoup(html, 'lxml')
dict_data = {'address':[], 'phone_no': [], 'email': []
}
crex = CommonRegex()
for link in soup.find_all('p'):
str_add = crex.street_addresses(link.get_text())
phone = crex.phones(link.get_text())
email = crex.emails(link.get_text())
if str_add:
dict_data['address'].append(str_add[0])
if phone:
dict_data['phone_no'].append(', '.join(phone))
if email:
dict_data['email'].append(email[0])
df = pd.DataFrame(dict_data)
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