如何获取 Google Classroom API 的课程 ID

清昌

我正在尝试使用Google Classroom API，我已经阅读了他们的文档，并且课程 ID 基本上用于所有内容，但他们从未解释在哪里可以找到课程的课程 ID。

当您创建课程时，该函数似乎也会返回课程 ID，但我想知道是否可以获取已存在课程的课程 ID。

肉桂

如文档的快速入门页面 ( https://developers.google.com/classroom/quickstart/python ) 所示，您可以运行一段代码来列出用户可以使用其凭据访问的前 10 门课程。然后，您可以print(course['id'])在迭代课程时添加一条语句，以打印您检索到的课程的 ID。python示例如下所示

from __future__ import print_function
import pickle
import os.path
from googleapiclient.discovery import build
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request

# If modifying these scopes, delete the file token.pickle.
SCOPES = ['https://www.googleapis.com/auth/classroom.courses.readonly']

def main():
    """Shows basic usage of the Classroom API.
    Prints the names of the first 10 courses the user has access to.
    """
    creds = None
    # The file token.pickle stores the user's access and refresh tokens, and is
    # created automatically when the authorization flow completes for the first
    # time.
    if os.path.exists('token.pickle'):
        with open('token.pickle', 'rb') as token:
            creds = pickle.load(token)
    # If there are no (valid) credentials available, let the user log in.
    if not creds or not creds.valid:
        if creds and creds.expired and creds.refresh_token:
            creds.refresh(Request())
        else:
            flow = InstalledAppFlow.from_client_secrets_file(
                'credentials.json', SCOPES)
            creds = flow.run_local_server(port=0)
        # Save the credentials for the next run
        with open('token.pickle', 'wb') as token:
            pickle.dump(creds, token)

    service = build('classroom', 'v1', credentials=creds)

    # Call the Classroom API
    results = service.courses().list(pageSize=10).execute()
    courses = results.get('courses', [])

    if not courses:
        print('No courses found.')
    else:
        print('Courses:')
        for course in courses:
            print(course['name'])
            print(course['id'])

if __name__ == '__main__':
    main()

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