如何STRUCT
在不按名称指定的情况下自动应用于表中的所有字段?
不起作用的示例:
WITH data as (
SELECT 'Alex' as name, 14 as age, 'something else 1' other_field
UNION ALL
SELECT 'Bert' as name, 14 as age, 'something else 2' other_field
UNION ALL
SELECT 'Chiara' as name, 13 as age, 'something else 3' other_field
)
SELECT AS STRUCT(SELECT * except (other_field) from data) as student_data
返回: Error: Scalar subquery cannot have more than one column unless using SELECT AS STRUCT to build STRUCT values at [9:17]
然而,这有效:
WITH data as (
SELECT 'Alex' as name, 14 as age, 'something else 1' other_field
UNION ALL
SELECT 'Bert' as name, 14 as age, 'something else 2' other_field
UNION ALL
SELECT 'Chiara' as name, 13 as age, 'something else 3' other_field
)
SELECT STRUCT(name,age) as student_data
from data
问题是,一旦我有 100 列,其中只有 5 列不属于,写出来让我发疯。有没有更简单的方法来使用某些版本的Select * Except()
?
下面是 BigQuery 标准 SQL
#standardSQL
WITH data AS (
SELECT 'Alex' AS name, 14 AS age, 'something else 1' other_field UNION ALL
SELECT 'Bert' AS name, 14 AS age, 'something else 2' other_field UNION ALL
SELECT 'Chiara' AS name, 13 AS age, 'something else 3' other_field
)
SELECT (
SELECT AS STRUCT * EXCEPT(other_field)
FROM UNNEST([t])
) AS student_data
FROM data t
带输出
Row student_data.name student_data.age
1 Alex 14
2 Bert 14
3 Chiara 13
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