有没有一种方法可以在回调中激活/停用悬停工具？
在尝试使用复选框切换线可见性的同时，我尝试执行此操作。每行都有一个悬停工具，当一行具有“ visible = false”时，我将相应工具的“名称”属性设置为虚拟字符串；否则，我将其设置为等于该行的初始“名称”属性。
它在第一次选中任何框时都有效，另外两行消失，并且悬停工具未显示在它们上面。但是重新激活悬浮工具不起作用。
这是我的尝试：
from bokeh.plotting import figure, output_file
from bokeh.models import CustomJS, HoverTool, CheckboxGroup, ColumnDataSource
from bokeh.layouts import gridplot
from bokeh.resources import CDN
from bokeh.embed import file_html
from collections import OrderedDict
TOOLTIPS = [ ("x", "$~x"), ("y", "$~y") ]
TOOLS = ['crosshair']
source = ColumnDataSource(data={'x':range(10),'y0':range(10),'y1':range(10)[::-1],'y2':[i**0.5 for i in range(10)]})
fig = figure(tools=TOOLS)
fig.tools[0].dimensions = 'height'
plots = []
plots.append( fig.line(x='x',y='y0', name="0", source=source) )
plots.append( fig.line(x='x',y='y1', name="1", source=source) )
plots.append( fig.line(x='x',y='y2', name="2", source=source) )
names = ['first','second','third']
ID=0
for plot in plots:
fig.add_tools( HoverTool(mode='vline',line_policy='interp',renderers=[plot],names=[str(ID)],tooltips=OrderedDict( [('name',names[ID])]+TOOLTIPS )) )
ID+=1
N_plots = range(len(plots))
checkbox = CheckboxGroup(labels=names,active=[],width=200)
checkbox_iterable =[('p'+str(i),plots[i]) for i in N_plots]+[('hover'+str(i),fig.tools[1:][i]) for i in N_plots]+[('checkbox',checkbox)]
checkbox_code = """var indexOf = [].indexOf;"""+''.join(['p'+str(i)+'.visible = indexOf.call(checkbox.active, '+str(i)+') >= 0;' for i in N_plots])
checkbox_code += ''.join(['if(p'+str(i)+'.visible) hover'+str(i)+'.names = ["'+str(i)+'"];' for i in N_plots])+''.join(['if(p'+str(i)+'.visible==false) hover'+str(i)+'.names = ["no"];' for i in N_plots])
checkbox_code += ''.join(['console.log(hover'+str(i)+'.names);' for i in N_plots])
checkbox.callback = CustomJS(args={key: value for key,value in checkbox_iterable}, code=checkbox_code)
grid = gridplot([[fig,checkbox]],toolbar_location='left')
outfile=open('hovtest.html','w')
outfile.write(file_html(grid,CDN,'test'))
outfile.close()
我使用bokeh 0.12.4
bokeh讨论小组的某个人找到了一种很好的方法（bokeh讨论线程）。
我们可以基于checkbox.active列表更改悬停工具的显示属性。这是示例代码：
from bokeh.plotting import figure, output_file
from bokeh.models import CustomJS, HoverTool, CheckboxGroup, ColumnDataSource
from bokeh.layouts import gridplot
from bokeh.resources import CDN
from bokeh.embed import file_html
from collections import OrderedDict
TOOLTIPS = [ ("x", "$~x"), ("y", "$~y") ]
TOOLS = ['crosshair']
data = {'x':range(10),
'y0':range(10),
'y1':range(10)[::-1],
'y2':[i**0.5 for i in range(10)]
}
source = ColumnDataSource(data=data)
fig = figure(tools=TOOLS)
fig.tools[0].dimensions = 'height'
plots = []
plots.append( fig.line(x='x',y='y0', name="first", source=source) )
plots.append( fig.line(x='x',y='y1', name="second", source=source) )
plots.append( fig.line(x='x',y='y2', name="third", source=source) )
checkbox = CheckboxGroup(
labels=[plot.name for plot in plots],
active=[0,1,2],
width=200,
callback = CustomJS( args=dict(p0=plots[0],p1=plots[1],p2=plots[2]),
code = """
p0.visible = cb_obj.active.includes(0);
p1.visible = cb_obj.active.includes(1);
p2.visible = cb_obj.active.includes(2);
"""
)
)
for ID,plot in enumerate(plots):
fig.add_tools(
HoverTool(
mode='vline',
line_policy='interp',
renderers=[plot],
names=[plot.name],
tooltips=OrderedDict( [('name',plot.name)]+TOOLTIPS ),
callback=CustomJS( args=dict(cb=checkbox),
code="""
if(!cb.active.includes(%d)) {
document.getElementsByClassName('bk-tooltip')[%d].style.display = 'none';
}
""" % (ID,ID)
)
)
)
grid = gridplot([[fig,checkbox]],toolbar_location='left')
outfile=open('hovtest.html','w')
outfile.write(file_html(grid,CDN,'hovtest'))
outfile.close()
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