我正在尝试清理句子以及要删除句子中的这些标签的方式（它们以下划线形式，后跟一个单词，例如“ _UH”）。基本上我想删除下划线之后的字符串（也删除下划线本身）
文本：
['hanks_NNS sir_VBP',
'Oh_UH thanks_NNS to_TO remember_VB']
需要的输出：
['hanks sir',
'Oh thanks to remember']
以下是我尝试的代码：
for i in text:
k= i.split(" ")
print (k)
for z in k:
if "_" in z:
j=z.replace("_",'')
print (j)
电流输出：
ThanksNNS
sirVBP
OhUH
thanksNNS
toTO
rememberVB
RemindVB
您可以使用re.sub()。匹配字符串中所需的子字符串，然后用空字符串替换子字符串：
import re
text = ['hanks_NNS sir_VBP', 'Oh_UH thanks_NNS to_TO remember_VB']
curated_text = [re.sub(r'_\S*', r'', a) for a in text]
print curated_text
输出：
['hanks sir', 'Oh thanks to remember']
正则表达式：
_\S* - Underscore followed by 0 or more non space characters
text = ['hanks_NNS sir_VBP', 'Oh_UH thanks_NNS to_TO remember_VB']
curated_text = [] # Outer container for holding strings in text.
for i in text:
d = [] # Inner container for holding different parts of same string.
for b in i.split():
c = b.split('_')[0] # Discard second element after split
d.append(c) # Append first element to inner container.
curated_text.append(' '.join(d)) # Join the elements of inner container.
#Append the curated string to the outer container.
print curated_text
输出：
['hanks sir', 'Oh thanks to remember']
实际上，您只想用'_'空字符串替换'_'，之后用空字符串替换字符。
for i in text:
k= i.split(" ")
print (k)
for z in k:
if "_" in z:
j=z.replace("_",'') # <--- 'hanks_NNS' becomes 'hanksNNS'
print (j)
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