我有一个代码输出的 XML 字符串。从输出中,我想加入两行,其中有一个'predicted_serotype'
字符串(这个字符串被称为diff_string
):
<result type="MLST" value="96">
<result_data type="profile" value="43,47,49,49,41,15,3"/>
<result_data type="QC_minimum_consensus_depth" value="7"/>
<result_data type="QC_max_percentage_non_consensus_base" value="10.0"/>
<result_data type="QC_percentage_coverage" value="100"/>
<result_data type="QC_minimum_consensus_depth_for_all_loci" value="7,17,27,10,25,18,22" diff:update-attr="value:7,17,27,10,24,18,22"/>
<result_data type="QC_complete_pileup" value="TRUE"/>
<result_data type="QC_mean_consensus_depth" value="17.67"/>
<result_data type="QC_max_percentage_non_consensus_base_for_all_loci" value="10.0, 6.25, 3.45, 9.09, 5.88, 5.26, 5.41"/>
<result_data type="QC_mean_consensus_depth_for_all_loci" value="17.67, 32.49, 34.09, 23.44, 35.57, 29.02, 39.08" diff:update-attr="value:17.67, 32.49, 34.09, 23.44, 34.24, 29.02, 39.08"/>
<result_data type="QC_traffic_light" value="GREEN"/>
<result_data diff:insert="" type="predicted_serotype" diff:add-attr="type;value" value="('Schwarzengrund (Achtman)', 168), ('Schwarzengrund (PHE)', 83), ('Blockley (Achtman)', 1), ('Uppsala (Achtman)', 1), ('Oslo (Achtman)', 1), ('Schwarzengru (Achtman)', 1), ('Iv Rough:Z4,Z32:- (Achtman)', 1)"/>
<result_data type="predicted_serotype" value="('Schwarzengrund (PHE)', 13)" diff:delete=""/>
</result>
<gastro_prelim_st reason="not novel" success="false">
<type st="96"/>
</gastro_prelim_st>
我已经编写了这段代码,但它只添加了一个新行而不是连接这两行:
diff_list = diff.split("\n")
for n,line in enumerate(diff_list):
if "predicted_serotype" in line:
diff_list[n] = "\n"+line.strip()
else:
diff_list[n]=line.rstrip()
print("\n".join(diff_list))
我想要的是这样的输出:
<result type="MLST" value="96">
<result_data type="profile" value="43,47,49,49,41,15,3"/>
<result_data type="QC_minimum_consensus_depth" value="7"/>
<result_data type="QC_max_percentage_non_consensus_base" value="10.0"/>
<result_data type="QC_percentage_coverage" value="100"/>
<result_data type="QC_minimum_consensus_depth_for_all_loci" value="7,17,27,10,25,18,22" diff:update-attr="value:7,17,27,10,24,18,22"/>
<result_data type="QC_complete_pileup" value="TRUE"/>
<result_data type="QC_mean_consensus_depth" value="17.67"/>
<result_data type="QC_max_percentage_non_consensus_base_for_all_loci" value="10.0, 6.25, 3.45, 9.09, 5.88, 5.26, 5.41"/>
<result_data type="QC_mean_consensus_depth_for_all_loci" value="17.67, 32.49, 34.09, 23.44, 35.57, 29.02, 39.08" diff:update-attr="value:17.67, 32.49, 34.09, 23.44, 34.24, 29.02, 39.08"/>
<result_data type="QC_traffic_light" value="GREEN"/>
<result_data diff:insert="" type="predicted_serotype" diff:add-attr="type;value" value="('Schwarzengrund (Achtman)', 168), ('Schwarzengrund (PHE)', 83), ('Blockley (Achtman)', 1), ('Uppsala (Achtman)', 1), ('Oslo (Achtman)', 1), ('Schwarzengru (Achtman)', 1), ('Iv Rough:Z4,Z32:- (Achtman)', 1)"/><result_data type="predicted_serotype" value="('Schwarzengrund (PHE)', 13)" diff:delete=""/>
</result>
<gastro_prelim_st reason="not novel" success="false">
<type st="96"/>
</gastro_prelim_st>
这应该可以解决问题,我们寻找第一次出现的带有 predict_serotype 的行,然后如果遇到另一个出现,我们将其删除并将其添加到第一次出现。
diff_list = diff.split("\n")
first_serotype_line_nbr = 0
for n,line in enumerate(diff_list):
if "predicted_serotype" in line:
if first_serotype_line_nbr == 0:
first_serotype_line_nbr = n
else:
diff_list[first_serotype_line_nbr] += line.rstrip()
del(diff_list[n])
else:
diff_list[n]=line.rstrip()
print("\n".join(diff_list))
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