我从 API 收到了一个类似于此的复杂 json 响应。
{
"result": "success",
"count": 100,
"details": [{
"unnecessaryDetails": "something",
"area": {
"name": "Test1"
}
},
{
"unnecessaryDetails": "something",
"area": {
"name": "Test2"
}
},
{
"unnecessaryDetails": "something",
"area": {
"name": "Test3"
}
}
]
}
我的结构是
struct Person {
var name: String
}
struct Response {
var result: String
var count: Int
var details: [Person]
}
我不想为我从响应中收到的所有内容创建属性。我不能要求后端开发人员只提供必要的详细信息。如何避免不必要的细节并仅使用需要的细节创建结构？
您可以跳过带有嵌套容器的中间数组和字典。
struct Person : Decodable {
let name: String
}
struct Response : Decodable {
let result: String
let count: Int
let details: [Person]
enum CodingKeys: String, CodingKey { case result, count, details }
enum DetailCodingKeys: String, CodingKey { case area }
init(from decoder : Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
result = try container.decode(String.self, forKey: .result)
count = try container.decode(Int.self, forKey: .count)
var detailContainer = try container.nestedUnkeyedContainer(forKey: .details)
var people = [Person]()
while !detailContainer.isAtEnd {
let areaContainer = try detailContainer.nestedContainer(keyedBy: DetailCodingKeys.self)
let person = try areaContainer.decode(Person.self, forKey: .area)
people.append(person)
}
details = people
}
}
然而，工作量比添加额外的结构要大得多
struct Response : Decodable {
let result: String
let count: Int
let details: [Detail]
}
struct Detail : Decodable {
let area : Person
}
struct Person : Decodable {
let name: String
}
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我来说两句