我想学习如何编码。
这是我想要的样子
Do you want strawberry ice cream? (y:n) n
Do you want chocolate ice cream? (y:n) y
Do you want mint ice cream? (y:n) n
Do you want vanilla ice cream? (y:n) y
那么输出将是：Here is your ice cream.或者如果你把 N 全部放入，You did not say yes to any.或者使用 else 语句：I didn't get that, try again.
非常感谢任何帮助，谢谢。
我的测试脚本：
def kind(chosenIce):
chosenIce=input("Do you want a ice cream (y:n) ")
if chosenIce1 == 'y':
ice1 = print("message")
if chosenIce2 == 'y':
ice2 = print("message")
if chosenIce1 == 'n':
ice1 = 0
if chosenIce2 == 'n':
ice2 = 0
else:
print("Sorry, I did not get that. Try again.")
kind(chosenIce)
正如一些人所说，你必须使用input和loop（即for loop或while loop）来实现你的目标。通过阅读您的帖子和评论，您似乎真的是 Python 的新手。因此，在下面，我为您提供了一个基本的工作流程，可以满足您的需求。有很多方法可以实现您的目标。您可以查看我的工作流程以获取灵感。
这是代码：
def kind(ices_cream):
choices = []
for ice in ices_cream:
chosenIce = input('Do you want "{}" ice cream (y:n) '.format(ice))
if chosenIce == 'y':
choices.append(ice)
elif chosenIce == 'n':
print("You refuse ", ice)
else:
print("Sorry, I did not get that. Try again.")
if len(choices):
print("\n", "You buy", ' and '.join(choices))
else:
print("\n", "You buy nothing!")
if __name__ == "__main__":
ices_cream = ["Chocolate", "Strawberry", "Mint", "Vanilla"]
kind(ices_cream)
输出：这是一个例子
Do you want "Chocolate" ice cream (y:n) y
Do you want "Strawberry" ice cream (y:n) n
You refuse Strawberry
Do you want "Mint" ice cream (y:n) y
Do you want "Vanilla" ice cream (y:n) n
You refuse Vanilla
You buy Chocolate and Mint
注意：您可以添加一个循环while来强制用户输入字符y或n。此外，如果你想做得好，你可以添加异常处理。
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