我正在用PHP开发应用程序，我需要使用日期和工作日的数字表示。
我尝试了以下方法：
$today = date("Y-m-d");
$number = date('N', strtotime($today));
echo "Today: " . $today . " weekday: " . $number . "<br>";
$today = strtotime($today);
$tomorrow = strtotime($today);
$tomorrow = strtotime("+1 day", $today);
$number2 = date('N', strtotime($tomorrow));
echo "Tomorrow: " . date('Y-m-d', $tomorrow) . " weekday: " . $number2 . "<br>";
Today: 2016-11-11 weekday: 5
Tomorrow: 2016-11-12 weekday: 4
这是不对的，因为明天的工作日应该是6而不是4。
有人可以帮我吗？
您的代码几乎没有错误，这里是有效的代码：
$today = date("Y-m-d");
$number = date('N', strtotime($today));
echo "Today: " . $today . " weekday: " . $number . "<br>";
$today = strtotime($today);
$tomorrow = strtotime($today);
$tomorrow = strtotime("+1 day", $today);
$number2 = date('N', $tomorrow);
echo "Tomorrow: " . date('Y-m-d', $tomorrow) . " weekday: " . $number2 . "<br>";
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