我不会检查我的网址statusCode是否等于200,我创建了一个函数,如果statusCode等于200,则返回一个布尔值,我正在使用dataTask,但是我不知道如何返回值:
class func checkUrl(urlString: String) -> Bool{
let urlPath: String = urlString
var url: NSURL = NSURL(string: urlPath)!
var request: NSURLRequest = NSURLRequest(url: url as URL)
var response: URLResponse?
let session = Foundation.URLSession.shared
var task = session.dataTask(with: request as URLRequest, completionHandler: {(data, response, error) in
if let error = error {
print(error)
}
if let data = data{
print("data =\(data)")
}
if let response = response {
print("url = \(response.url!)")
print("response = \(response)")
let httpResponse = response as! HTTPURLResponse
print("response code = \(httpResponse.statusCode)")
if httpResponse.statusCode == 200{
return true
} else {
return false
}
}
})
task.resume()
}
中的返回值if else
返回错误:
void函数中非预期的非无效返回值
为了返回值,您应该使用块。尝试像这样声明您的功能:
class func checkUrl(urlString: String, finished: ((isSuccess: Bool)->Void) {
let urlPath: String = urlString
var url: NSURL = NSURL(string: urlPath)!
var request: NSURLRequest = NSURLRequest(url: url as URL)
var response: URLResponse?
let session = Foundation.URLSession.shared
var task = session.dataTask(with: request as URLRequest, completionHandler: {(data, response, error) in
if let error = error {
print(error)
}
if let data = data{
print("data =\(data)")
}
if let response = response {
print("url = \(response.url!)")
print("response = \(response)")
let httpResponse = response as! HTTPURLResponse
print("response code = \(httpResponse.statusCode)")
if httpResponse.statusCode == 200{
finished(isSuccess: true)
} else {
finished(isSuccess: false)
}
}
})
task.resume()
}
然后这样称呼它:
checkUrl("http://myBestURL.com", finished { isSuccess in
// Handle logic after return here
})
希望这会有所帮助。
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