使用正则表达式，提取可能包含嵌套引号的带引号的字符串

我有以下字符串：

'Well, I've tried to say "How Doth the Little Busy Bee," but it all came different!' Alice replied in a very melancholy voice. She continued, 'I'll try again.'

现在，我希望提取以下引号：

1. Well, I've tried to say "How Doth the Little Busy Bee," but it all came different!
2. How Doth the Little Busy Bee,
3. I'll try again.

我尝试了以下代码，但没有得到想要的东西。该[^\1]*不会按预期工作。还是其他地方的问题？

import re

s = "'Well, I've tried to say \"How Doth the Little Busy Bee,\" but it all came different!' Alice replied in a very melancholy voice. She continued, 'I'll try again.'"

for i, m in enumerate(re.finditer(r'([\'"])(?!(?:ve|m|re|s|t|d|ll))(?=([^\1]*)\1)', s)):
    print("\nGroup {:d}: ".format(i+1))
    for g in m.groups():
        print('  '+g)