如何在Objective-C中处理用于JSON格式的嵌入式数组

马克思主义

我有一本字典array：

     {
        "encoding": "320", 
        "format": "MP3", 
        "media": "CD", 
        "name": "foo", 
        "remaster_title": ""
    }, 
    {
        "encoding": "V0 (VBR)", 
        "format": "MP3", 
        "media": "CD", 
        "name": "bar", 
        "remaster_title": ""
    }, 
    {
        "encoding": "Lossless", 
        "format": "FLAC", 
        "media": "CD", 
        "name": "bar", 
        "remaster_title": "hoho"
    }

我想将它们分开，以便它们唯一。例如，应该只有一个，name所以会有两个部分：foo和bar。

然后在每个name（foo或bar）中应该有remaster_title（for foo：以及barboth：和hoho）...。

顺序应为：name > remaster_title > media > format > encoding。

我认为如果我可以使用类似以下格式的文件，则可以使用：

music[name][remaster_title][media][format] = encoding

这样所有的键都可以合并吗？

我努力了：

+(NSMutableDictionary*)handleReturnedArtistJson:(NSDictionary*)json{
    NSMutableDictionary *music = [[NSMutableDictionary alloc] init];
    for(NSDictionary *result in json[@"response"][@"group"]) {
        NSString* release_type = result[@"releaseType"];
        NSString* name = result[@"groupName"];

        if (![release_type  isEqual: @"Compilation"]){
            for (NSDictionary *subgroup in result[@"subgroup"]){
                NSString* media = subgroup[@"media"];
                NSString* remaster_title = subgroup[@"remasterTitle"];
                NSString* format = subgroup[@"format"];
                NSString* encoding = subgroup[@"encoding"];

                music[name][remaster_title][media][format] = encoding;
            }
        }
    }
    return music;
}

但NSLog(@"%@",music);什么也没返回。

亚历克斯·诺拉斯科

评论区域太小，无法提出一些问题，但让我们假设一些事情。您想将JSON解析为对象树。让我们看看这段代码是否可以帮助您。

#import <Foundation/Foundation.h>

typedef NSMutableDictionary<NSString*, NSString*> formatDictionary;
typedef NSMutableDictionary<NSString*, formatDictionary*> mediaDictionary;
typedef NSMutableDictionary<NSString*, mediaDictionary*> titleDictionary;
typedef NSMutableDictionary<NSString*, titleDictionary*> nameDictionary;

@interface DataSource : NSObject
- (nameDictionary*)parseJSONFile:(NSString *)jsonFile error:(NSError *__autoreleasing *)outError;
@end

实作

@implementation DataSource

- (NSString *)valueOrDefaultFromDictionary:(NSDictionary *) dictionary forKey: (NSString *) key
{
    NSString * value = dictionary[key];
    if (![value length]) {
        return @"";
    }
    return value;
}

- (NSArray *)jsonToArray:(NSString *)jsonFile error:(NSError *__autoreleasing *)outError
{
    NSString *path  = [[NSBundle mainBundle] pathForResource:jsonFile ofType:@"json"];
    NSString *jsonString = [[NSString alloc] initWithContentsOfFile:path encoding:NSUTF8StringEncoding error:nil];
    NSError *jsonError;
    NSArray *jsonDataArray = [NSArray new];
    jsonDataArray = [NSJSONSerialization JSONObjectWithData:[jsonString dataUsingEncoding:NSUTF8StringEncoding] options:kNilOptions error:&jsonError];

    if (jsonDataArray == nil) {
        if (outError) {
            *outError = [NSError errorWithDomain:@"yourdomain" code:-42 userInfo:@{NSUnderlyingErrorKey: jsonError}];
        }
        return nil;
    }
    return jsonDataArray;
}


- (nameDictionary*)parseJSONFile:(NSString *)jsonFile error:(NSError *__autoreleasing *)outError
{
    NSArray * jsonDataArray = [self jsonToArray:jsonFile error:outError];
    if (!jsonDataArray) {
      return nil;
    }
    nameDictionary* music = [nameDictionary new];

    [jsonDataArray enumerateObjectsUsingBlock:^(id _Nonnull obj, NSUInteger idx, BOOL * _Nonnull stop) {
        NSString * name = [self valueOrDefaultFromDictionary:obj forKey:@"name"];
        NSString * title = [self valueOrDefaultFromDictionary:obj forKey:@"remaster_title"];
        NSString * media = [self valueOrDefaultFromDictionary:obj forKey:@"media"];
        NSString * format = [self valueOrDefaultFromDictionary:obj forKey:@"format"];
        NSString * encoding = [self valueOrDefaultFromDictionary:obj forKey:@"encoding"];
        music[name] = [@{title: [@{media: [@{format:encoding} mutableCopy] } mutableCopy] } mutableCopy];
    }];
    return music;
}
@end