没有模型的 Django REST API 框架

我创建了一个简单的 html 页面，它允许我上传图像并将其存储在目录中，而无需使用模型。我的目标是使用 REST API 框架并显示在 REST API 中上传的特定图像，即

{"image": "uploaded_image_by_user"}

如何为此 REST API 创建 POST 和 GET 方法？

我尝试这样做，但它不能正常工作。有没有正确的方法来做到这一点？或者更确切地说，有人知道创建没有模型的 REST API 的基本方法吗？仅供参考，我是 Django 的新手

我目前的代码：

视图.py

from django.shortcuts import render
from django.db import models
from django.views.generic import View, TemplateView, CreateView
from image_app.forms import ImageForm
from django.contrib.messages.views import SuccessMessageMixin
import requests
from django.http import HttpResponse
from django.shortcuts import get_object_or_404
from rest_framework.views import APIView
from rest_framework.response import Response
from rest_framework import status
from image_app.serializers import ImageSerializer
from django.http import Http404
import os, sys
from rest_framework.parsers import FileUploadParser
from django.http import HttpResponseRedirect
from django.core.files.storage import FileSystemStorage
from django.conf import settings
from django.contrib import messages


class BaseView(TemplateView):
    template_name = "base.html"

def upload(request):
    if request.method == 'POST':
        filename = rename()
        uploaded_file = request.FILES['image']
        fs = FileSystemStorage(location=settings.PRIVATE_STORAGE_ROOT)
        name = fs.save(uploaded_file.name, uploaded_file)
        messages.success(request, 'Uploaded Image Successfully.')
        return HttpResponseRedirect("base.html")
    return render(request, "insert_image.html")

class ImageList(APIView):

    def get(self, request, format = None):
        file = os.listdir(r'path_name_of_uploaded_image')[0]
        print(file)
        if file:
            images = [{"similar_image": file}]
            serializer = ImageSerializer(images, many = True).data
            return Response({'serializer': serializer}, status = status.HTTP_201_CREATED) 
        else:
            return Response({"similar_image": "Similar images are non existent"}, status = 400)

    def post(self, request):
        parser_classes = (FileUploadParser,)
        file = request.data.get('image', None)
        return Response({"similar_image": file}, status = 200)

序列化程序.py

from rest_framework import serializers

class ImageSerializer(serializers.Serializer):
    similar_image = serializers.CharField()