我正在尝试预测数组的样本外值。Python代码:
import pandas as pd
import numpy as np
from statsmodels.tsa.arima_model import ARIMA
dates = pd.date_range('2012-07-09','2012-07-30')
series = [43.,32.,63.,98.,65.,78.,23.,35.,78.,56.,45.,45.,56.,6.,63.,45.,64.,34.,76.,34.,14.,54.]
res = pd.Series(series, index=dates)
r = ARIMA(res,(1,2,0))
pred = r.predict(start='2012-07-31', end='2012-08-31')
我收到这个错误,我看到我给出了两个参数,但是编译器返回了我给出的3。
Traceback (most recent call last):
File "XXXXXXXXX/testfile.py", line 12, in <module>
pred = r.predict(start='2012-07-31', end='2012-08-31')
TypeError: predict() takes at least 2 arguments (3 given)
请帮忙
的呼叫签名ARIMA.predict
为
predict(self, params, start=None, end=None, exog=None, dynamic=False)
因此,当您调用时r.predict(start='2012-07-31', end='2012-08-31')
,self
被绑定到r
,并且值被绑定到start
,end
但是所需的位置params
不被绑定。这就是为什么你得到错误
TypeError: predict() takes at least 2 arguments (3 given)
不幸的是,错误消息具有误导性。“给定3”指的是r
,start
和end
。“ 2个参数”是指两个必需的参数,self
和params
。问题是没有给出所需的位置参数params
。
要解决此问题,您需要参数。通常,您可以通过拟合找到这些参数:
r = r.fit()
致电之前
pred = r.predict(start='2012-07-31', end='2012-08-31')
r.fit()
返回statsmodels.tsa.arima_model.ARIMAResultsWrapper
具有参数“烘焙”的,因此调用ARIMAResultWrapper.fit
不需要通过params
。
import pandas as pd
import numpy as np
from statsmodels.tsa.arima_model import ARIMA
dates = pd.date_range('2012-07-09','2012-07-30')
series = [43.,32.,63.,98.,65.,78.,23.,35.,78.,56.,45.,45.,56.,6.,63.,45.,64.,34.,76.,34.,14.,54.]
res = pd.Series(series, index=dates)
r = ARIMA(res,(1,2,0))
r = r.fit()
pred = r.predict(start='2012-07-31', end='2012-08-31')
print(pred)
产量
2012-07-31 -39.067222
2012-08-01 26.902571
2012-08-02 -17.027333
...
2012-08-29 0.532946
2012-08-30 0.532447
2012-08-31 0.532780
Freq: D, dtype: float64
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