使用R中的lubridate从日期确定季节

拉特尼

我有一个很大的数据集,其中DateTime包含一个包含POSIXct-Values列。我需要根据该DateTime确定季节(冬季-夏季)我创建了一个在小型数据集上可以正常运行的函数,但是在大型数据集上使用时会崩溃。有人可以看到我的错误吗?

我创建了4个函数:

  • 3个子函数,这样我就可以使用* apply函数进行逻辑比较和选择
  • 1确定季节的功能

功能如下:

require(lubridate)

# function for logical comparison (to be used in *apply)
greaterOrEqual <- function(x,y){
  ifelse(x >= y,T,F)
}

# function for logical comparison (to be used in *apply)
less <- function(x,y){
  ifelse(x < y,T,F)
}

# function for logical comparison (to be used in *apply)
selFromLogic <- function(VecLogic,VecValue){
  VecValue[VecLogic]
}

# Main Function to determine the season
getTwoSeasons <- function(input.date) {
  Winter1Start <- as.POSIXct("2000-01-01 00:00:00", tz = "UTC")
  Winter1End <- as.POSIXct("2000-04-15 23:59:59", tz = "UTC")

  SummerStart <- Winter1End + 1
  SummerEnd <- as.POSIXct("2000-10-15 23:59:59", tz = "UTC")

  Winter2Start <- SummerEnd + 1
  Winter2End <- as.POSIXct("2000-12-31 00:00:00", tz = "UTC")

  year(input.date) <- year(Winter1Start)
  attr(input.date, "tzone") <- attr(Winter1Start, "tzone")

  SeasonStart <- c(Winter1Start,SummerStart,Winter2Start)
  SeasonsEnd <- c(Winter1End,SummerEnd,Winter2End)
  Season_names <- as.factor(c("WinterHalfYear","SummerHalfYear","WinterHalfYear"))

  Season_select <- sapply(SeasonStart, greaterOrEqual, x = input.date) & sapply(SeasonsEnd, less, x = input.date)
  Season_return <- apply(Season_select,MARGIN = 1,selFromLogic,VecValue = Season_names)

  return(Season_return)
}

这是测试功能的一种方法:

dates <- Sys.time() + seq(0,10000,10)
getTwoSeasons(dates)

我将不胜感激,这让我发疯!

拉特尼

我将@Lars Arne Jordanger的更为优雅的方法打包为一个函数:

getTwoSeasons <- function(input.date){
  numeric.date <- 100*month(input.date)+day(input.date)
  ## input Seasons upper limits in the form MMDD in the "break =" option:
  cuts <- base::cut(numeric.date, breaks = c(0,415,1015,1231)) 
  # rename the resulting groups (could've been done within cut(...levels=) if "Winter" wasn't double
  levels(cuts) <- c("Winter", "Summer","Winter")
  return(cuts)
}

在一些样本数据上对其进行测试似乎可以正常工作:

getTwoSeasons(as.POSIXct("2016-01-01 12:00:00")+(0:365)*(60*60*24))

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