我尝试发送带有附件的电子邮件(一个pdf文件),但是接收者收到的文件具有不同的名称,而.pdf结尾没有变化。文件名是希腊文。
try {
MimeMessage message = new MimeMessage(session);
message.setFrom(new InternetAddress("[email protected]"));
message.setRecipients(Message.RecipientType.TO, InternetAddress.parse(mail));
message.setSubject(title,"utf-8");
// Create the message part
BodyPart messageBodyPart = new MimeBodyPart();
// Now set the actual message
messageBodyPart.setText("This is message body");
// Create a multipar message
Multipart multipart = new MimeMultipart();
// Set text message part
multipart.addBodyPart(messageBodyPart);
// Part two is attachment
messageBodyPart = new MimeBodyPart();
String filename = "file.pdf";
String f = name + " Πρόγραμμα Ιανουάριος 2016.pdf"; // the desired name of the file
DataSource source = new FileDataSource(filename);
messageBodyPart.setDataHandler(new DataHandler(source));
messageBodyPart.setFileName(MimeUtility.encodeText(f, "UTF-8", null));
multipart.addBodyPart(messageBodyPart);
// Send the complete message parts
message.setContent(multipart);
Transport.send(message);
System.out.println("Mail " + mail +" sent");
} catch (MessagingException e) {
throw new RuntimeException(e);
}
该name
是一个字符串变量,并事先得到一个值。奇怪的是,如果我有String f = name + " αααα.pdf"
接收器,则成功获取带有名称的pdf文件,Ρουβάς αααα.pdf
但是如果我有此String f = name + " Πρόγραμμα Ιανουάριος 2016.pdf";
,则不会。他越来越喜欢=_UTF-8_B_zpzOtc Dz4POsc67zrHPgiDOmc6xzr3Ov8 FzqzPgc65zr_Pgi___ ___filename_1=__5wZGY=_=
我添加了message.writeTo(System.out);
,我得到了:
MIME-Version: 1.0
Content-Type: multipart/mixed;
bou
ndary="----=_Part_0_1825884453.1457025565509"
------=_Part_0_1825884453.1457025565509
Content-Type: text/plain; charset=us-ascii
Content-Transfer-Encoding: 7bit
This is message body
------=_Part_0_1825884453.1457025565509
Content-Type: application/octet-stream;
name*0="=?UTF-8?B?zpzOtc+Dz4POsc67zrHPgiDOmc6xzr3Ov8+FzrHPgc6vzr/Pgi";
name*1="Ay?=
=?UTF-8?B?MDE2zpnOsc69zr/Phc6sz4HOuc6/z4IgMjAxNi5wZGY=?";
name*2="="
Content-Transfer-Encoding: base64
Content-Disposition: attachment;
filename*0="=?UTF-8?B?zpzOtc+Dz4POsc67zrHPgiDOmc6xzr3Ov8+FzrHPgc6vzr/Pgi";
filename*1="Ay?=
=?UTF-8?B?MDE2zpnOsc69zr/Phc6sz4HOuc6/z4IgMjAxNi5wZGY=?";
filename*2="="
用props.setProperty("mail.mime.encodeparameters", "false");
或true
MIME-Version: 1.0
Content-Type: multipart/mixed;
boundary="----=_Part_0_797681969.1457074816557"
------=_Part_0_797681969.1457074816557
Content-Type: text/plain; charset=us-ascii
Content-Transfer-Encoding: 7bit
This is message body
------=_Part_0_797681969.1457074816557
Content-Type: application/octet-stream; name="?????????? 2016.pdf"
Content-Transfer-Encoding: base64
Content-Disposition: attachment;
filename*=Cp1252''%3F%3F%3F%3F%3F%3F%3F%3F%3F%3F%202016.pdf
因为您是自己对文件名进行编码,所以使用的是非标准MIME编码格式,如JavaMail FAQ中所述。然后,使用标准RFC 2231技术将该非标准编码文本拆分为多个参数。非标准格式和标准格式的这种混合可能会导致邮件阅读器混乱。
尝试通过删除对的调用,让JavaMail为您进行编码MimeUtility.encodeText
。如果这不起作用,请将System属性mail.mime.encodeparameters
设置false
为禁用RFC 2231编码。
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