我已经问过我周围的人并无数次尝试获得这个修复程序。该程序应该能够根据需要多次添加用户的网站和密码，并显示他们选择的网站和密码。
现在，当你回答would you like to add another website?跟是它不到风度再要求一个新的网站名称和密码，但只是重复的问题would you like to add another website?，还当你在一个网站的名称和密码，答案已经进入would you like to add another website?与无则选择选项1，看现有的帐户，它重复would you like to add another website?，当这甚至应该出现在选项一时
输入以及它应该如何输出：
1) 找到您现有的密码
2) 为您的应用程序保存一个新密码
3) 查看您的密码柜摘要
4) 成功退出密码柜1
您没有存储的网站和密码
1) 找到您现有的密码
2) 为您的应用程序保存一个新密码
3) 查看您的密码柜摘要
4) 成功退出密码柜2
您要添加的网站/应用程序的名称是什么？Instagram
您的 {instagram} 帐户的密码是什么？鲍勃91
您想添加另一个网站吗？是的
您要添加的网站/应用程序的名称是什么？Facebook
您的 {facebook} 帐户的密码是什么？鲍勃92
您想添加另一个网站吗？不
1) 找到您现有的密码
2) 为您的应用程序保存一个新密码
3) 查看您的密码柜摘要
4) 成功退出密码柜1
输入您要查找Instagram密码的应用程序网站
名称
= Instagram 密码 = bob91
完整代码：
vault_apps = []
app_name = ""
def locker_menu_func():
print('''You have opened the locker,
Please select what you would like to do,''')
locker_menu_var = input('''Press: \n1) find your existing passwords \n2) save a new password for your apps\n3) see a summary of your password locke \n4) exit password locker successfully\n---------------------------------------------------------------------------------
''')
print('''----------------------------------------------------------------''')
while True:
if locker_menu_var == "1":
while len(vault_apps) < 1:
print('''you have nothing stored''')
if len(vault_apps) > 1:
print(vault_apps)
break
break
if locker_menu_var == "2":
app_name = input('''
What is the name of the website/app your are adding?
''')
app_password = input('''What is the password of your {} account?
'''.format(app_name))
vault_apps.append([app_name, app_password])
while True:
ask_again = input('''Would you like to add another app and password?
''')
if ask_again.lower() == "yes":
locker_menu_var = "2"
elif ask_again.lower() == "no":
locker_menu_func()
else:
print("please enter a valid response") #should repeat if user want to add another website
这个逻辑是有缺陷的。一旦进入无限while循环，就无法退出，只能输入“no”。当您输入“yes”时，locker_menu_var 的值会发生变化，但您不会退出循环，因此它会不断重复相同的菜单。
while True:
ask_again = input('''Would you like to add another app and password?
''')
if ask_again.lower() == "yes":
locker_menu_var = "2"
elif ask_again.lower() == "no":
locker_menu_func()
您正在混合循环和递归，这让事情变得混乱。一种简单的方法是：
vault_apps = []
def locker_menu():
# the entry message
msg = '''You have opened the locker, Please select what you would like to do,'''
print(msg, end="\n\n")
# nume options
menu = ["1) find your existing passwords",
"2) save a new password for your apps",
"3) see a summary of your password locker",
"4) exit password locker successfully"]
menu_string = f"Press:\n{menu[0]}\n{menu[1]}\n{menu[2]}\n{menu[3]}\n"
# now enter the loop
while True:
# input variable
# NOTE: This variable is inside the loop,
# so that the user can enter the value everytime
# the loop repeates.
locker_menu_var = input(menu_string)
if locker_menu_var == "1":
# retrieve password for an existing record.
# although it's not a good idea to just print
# all the records, I am not changing your application logic
# because I don't see any use in it.
# you missed one case in your logic,
# which I have fixed here.
if len(vault_apps) == 0:
print("you have nothing stored")
else:
print(vault_apps)
elif locker_menu_var == "2":
# for a new entry
# enter your logic here
an = input("app name: ")
passw = input("password: ")
vault_apps.append([an, passw])
done = False # flag for exiting
while not done:
inp = input("enter another?")
if inp == "yes":
# enter logic here
an = input("app name: ")
passw = input("password: ")
vault_apps.append([an, passw])
else:
done = True
elif locker_menu_var == "3":
# do something
pass
elif locker_menu_var == "4":
return
if __name__ == "__main__":
locker_menu()
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