我试图在一个像素一个像素的基础上绘制谢尔宾斯基三角形，它会在窗口大小改变时调整自身大小。我相信我已经完成了大部分项目，但我不太知道如何从paintComponent方法之外的单独递归函数中绘制矩形。
public class SierpTriangle extends JPanel
{
public final int x = this.getWidth();
public final int y = this.getHeight();
public final int side = getsize();
public int getsize()
{
int width = this.getWidth();
int height = this.getHeight();
if (width <= height)
{
return width;
}
else
{
return height;
}
}
public void paintComponent(Graphics g)
{
super.paintComponent(g);
drawSierpTriangle(this.x, this.y, this.side);
g.drawRect(x,y,1,1);
}
public void drawSierpTriangle(int x, int y, int size)
{
if (size == 1)
{
//Draw rectangle? This is where I need help
g.drawRect(x,y,1,1); //this does not work, passing Graphics g into the method also does not work
}
else
{
drawSierpTriangle(x/2, y, size/2);
drawSierpTriangle(x,y/2,size/2);
drawSierpTriangle(x/2,y/2,size/2);
}
}
public static void main(String[] args)
{
new SierpFrame();
}
}
传递GraphicsfrompaintComponent到drawSierpTriangle
public void paintComponent(Graphics g)
{
super.paintComponent(g);
drawSierpTriangle(g, this.x, this.y, this.side);
g.drawRect(x,y,1,1);
}
public void drawSierpTriangle(Graphics g, int x, int y, int size)
{
if (size == 1)
{
//Draw rectangle? This is where I need help
g.drawRect(x,y,1,1); //this does not work, passing Graphics g into the method also does not work
}
else
{
drawSierpTriangle(g, x/2, y, size/2);
drawSierpTriangle(g, x,y/2,size/2);
drawSierpTriangle(g, x/2,y/2,size/2);
}
}
这会导致： 在第一次递归调用该方法时，线程“AWT-EventQueue-0”中的异常 java.lang.StackOverflowError。任何输入？
public final int side = getsize();
将side永远0。
用更像……的东西代替它
public int getSide() {
int width = this.getWidth();
int height = this.getHeight();
if (width <= height) {
return width;
} else {
return height;
}
}
public void paintComponent(Graphics g) {
super.paintComponent(g);
int side = getSide();
if (side == 0) return;
drawSierpTriangle(g, this.x, this.y, side);
g.drawRect(x, y, 1, 1);
}
这将在side每次绘制组件时进行评估。如果 side 是，它也将跳过绘制形状0
你也会遇到同样的问题xand y，因为状态永远不会改变
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我来说两句