我正在使用下面的 php 代码在我的文件中使用 json 但我没有得到输出。我需要从 Json array 打印图像 url。任何人都可以帮忙。
Json 数据是：
{
"pagination": {},
"data": [
{
"id": "1980025670135540608_1039191866",
"user": {},
"images": {
"thumbnail": {
"width": 150,
"height": 150,
"url": "https://scontent.cdninstagram.com/vp/d3d00967ec82131dedfdddb0cb8f8bc7/5CFCE4F1/t51.2885-15/e35/s150x150/50959433_383283642451967_2367872435860221844_n.jpg?_nc_ht=scontent.cdninstagram.com"
},
"low_resolution": {
"width": 320,
"height": 320,
"url": "https://scontent.cdninstagram.com/vp/5cb939b696c2d5a0211572bd0e965bee/5CF41C01/t51.2885-15/e35/s320x320/50959433_383283642451967_2367872435860221844_n.jpg?_nc_ht=scontent.cdninstagram.com"
},
"standard_resolution": {
"width": 640,
"height": 640,
"url": "https://scontent.cdninstagram.com/vp/411df4ade429230dee0ab3631d25a6eb/5CE56DB3/t51.2885-15/e35/50959433_383283642451967_2367872435860221844_n.jpg?_nc_ht=scontent.cdninstagram.com"
}
},
"created_time": "1550257475",
"caption": null,
"user_has_liked": false,
"likes": {
"count": 0
},
"tags": {},
"filter": "Normal",
"comments": {
"count": 0
},
"type": "image",
"link": "https://www.instagram.com/p/Bt6dts6lWuA/",
"location": null,
"attribution": null,
"users_in_photo": {}
},
{
"id": "1979798389190546391_1039191866",
"user": {
"id": "1039191866",
"full_name": "Jagjeet Kumar",
"profile_picture": "https://scontent.cdninstagram.com/vp/9871a297c832e1b1ef249028856af412/5CFC0D7D/t51.2885-19/11931260_1465802173750145_760962573_a.jpg?_nc_ht=scontent.cdninstagram.com",
"username": "jagjeet_k"
},
"images": {
"thumbnail": {
"width": 150,
"height": 150,
"url": "https://scontent.cdninstagram.com/vp/5f7e27fbf6d878bb85be23b70b637866/5CF8244F/t51.2885-15/e35/s150x150/50801938_1432836230186365_4210258679421826307_n.jpg?_nc_ht=scontent.cdninstagram.com"
},
"low_resolution": {
"width": 320,
"height": 320,
"url": "https://scontent.cdninstagram.com/vp/16376fe1eb033705d1c7b1f394bef013/5CE38537/t51.2885-15/e35/s320x320/50801938_1432836230186365_4210258679421826307_n.jpg?_nc_ht=scontent.cdninstagram.com"
},
"standard_resolution": {
"width": 640,
"height": 640,
"url": "https://scontent.cdninstagram.com/vp/c51878930ed8c98a595f16299f5c18d7/5CF9E7CA/t51.2885-15/sh0.08/e35/s640x640/50801938_1432836230186365_4210258679421826307_n.jpg?_nc_ht=scontent.cdninstagram.com"
}
},
"created_time": "1550230381",
"caption": null,
"user_has_liked": false,
"likes": {
"count": 1
},
"tags": {},
"filter": "Crema",
"comments": {
"count": 1
},
"type": "image",
"link": "https://www.instagram.com/p/Bt5qCVCl9PX/",
"location": null,
"attribution": null,
"users_in_photo": {}
}
],
"meta": {
"code": 200
}
}
我正在使用的 PHP 代码：
<?php
$instagram_feed_data = json_decode($mediacount, true);
foreach ($instagram_feed_data->data as $item) {
$img_url = $item['images']['low_resolution']['url'];
?>
<img src="<?= $img_url; ?>">
<?php
}
我必须打印低分辨率数组中的图像 url。
$instagram_feed_data = json_decode($mediacount, true);
向第二个参数传递一个真值json_decode()告诉 PHP 你想要一个数组而不是一个对象。所以你不能像这样用对象句柄取消引用它：
foreach ($instagram_feed_data->data as $item) {
你想要一个像这样的数组引用：
foreach ($instagram_feed_data['data'] as $item) {
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