此代码采用有序（从最高分到最低分）的元组列表，并收集最高、第二高和第三高得分者的姓名和得分。如果他们是平局，则两个名字都将附加到同一个列表中。
myresults=[('Raven', '18'), ('Cobra', '8'), ('Lion', '6'), ('Otter', '2')]
FirstScore=myresults[0][1]
SecondHighestScore=0
ThirdHighestScore=0
for i in myresults:
if i[1]==FirstScore:
FirstPlacePatrols.append(i[0])
for i in myresults:
print(i[1])
print(repr(i[1]))
if int(i[1])<int(FirstScore):
if int(i[1])>=SecondHighestScore:
print(i[1])
i[1]=SecondHighestScore
SecondPlacePatrols.append(i[0])
for i in myresults:
if int(i[1])<SecondHighestScore:
if int(i[1])>=ThirdHighestScore:
i[0]=ThirdHighestScore
ThirdPlacePatrols.append(i[0])
print(FirstPlacePatrols)
print(FirstScore)
print(SecondPlacePatrols)
print(SecondHighestScore)
print(ThirdPlacePatrols)
print(ThirdHighestScore)
然而，
i[1]=SecondHighestScore
产量，
TypeError: 'tuple' object does not support item assignment
尽管，
print(repr(i[1]))
屈服，
'18'
这显然不是元组。
这是我的解决方案：
from collections import defaultdict
given_list = [('Raven', '18'), ('Cobra', '8'), ('Lion', '6'), ('Python', '6'),('Otter', '2')]
reversed_dict = defaultdict(list)
for key,value in given_list:
reversed_dict[int(value)].append(key)
for k in reversed(sorted(reversed_dict)[-3:]):
print(k,reversed_dict[k])
输出：
18 ['Raven']
8 ['Cobra']
6 ['Lion', 'Python']
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