如何根据另一个对象数组的值创建一个对象数组？

老阿琼

我有 8 个球员ab, cd, ef, gh, ij, kl, mn,op他们的比赛数据存储在一个对象数组中

  matchData=[
              {player1:'ab',player2:'cd',winner:'ab',looser:'cd'},
              {player1:'ef',player2:'gh',winner:'gh',looser:'ef'},
              {player1:'ij',player2:'kl',winner:'ij',looser:'kl'},
              {player1:'mn',player2:'op',winner:'mn',looser:'op'},
              {player1:'ab',player2:'cd',winner:'ab',looser:'cd'},
              {player1:'ij',player2:'kl',winner:'kl',looser:'ij'},
              {player1:'ij',player2:'kl',winner:'ij',looser:'kl'}]

我想从上面的比赛数据中得到顶级球员。顶级球员是胜率最高的球员

winrate=(number of matches won/total number of matches played)*100

并且还想获得看起来像的对象数组，

PlayerData=[{ab:87},{cd:78},{ef:57},{gh:75},{ij:47},{kl:14},{mn:65},{op:44}]

我怎样才能做到这一点？

尼蒂什·纳朗

您可以循环遍历数据并为每个获胜者/松散者创建新数组，如果获胜则加 1，如果输则加 0。然后计算新数组对象的获胜百分比。

matchData = [
              {player1:'ab',player2:'cd',winner:'ab',looser:'cd'},
              {player1:'ef',player2:'gh',winner:'gh',looser:'ef'},
              {player1:'ij',player2:'kl',winner:'ij',looser:'kl'},
              {player1:'mn',player2:'op',winner:'mn',looser:'op'},
              {player1:'ab',player2:'cd',winner:'ab',looser:'cd'},
              {player1:'ij',player2:'kl',winner:'kl',looser:'ij'},
              {player1:'ij',player2:'kl',winner:'ij',looser:'kl'}
]

let tempRes = {}
for (let d of matchData) {
  let { winner, looser } = d
  
  tempRes[winner] = (tempRes[winner] || []).concat(1)
  tempRes[looser] = (tempRes[looser] || []).concat(0)
  
}

let res = [], topPlayers = [], topValue = 0
for (let [key, value] of Object.entries(tempRes)) {
  let winPercent = (value.reduce((a,b) => a + b) / value.length) * 100
  res.push({ [key]: winPercent })

  winPercent == topValue && (topPlayers.push(key))
  winPercent > topValue && (topValue = winPercent, topPlayers = [key])
}

console.log('Top Player ', topPlayers)
console.log('Result ',res)

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