当我在 python unittest 的 setUp 中保存一个实例时,我弹出了 2 个错误:
sqlite3.IntegrityError:NOT NULL 约束失败: registro_c170.reg_c100_id
和
peewee.OperationalError:连接已经打开。(这是为我的测试类中的每个 test_method 引发的。)
语境:
我对面向对象编程和单元测试很陌生。我正在使用 python 来构建寄存器层次结构的模型。该登记册保存有关税收和问责制的信息。
模型:
from peewee import *
db = SqliteDatabase('pis_cofins.db')
class BaseModel(Model):
class Meta:
database = db
class Registro_C100(BaseModel):
"""
"""
# Atributos
x = CharField()
y = CharField()
@property
def dados(self):
# some property
@dados.setter
def dados(self, novos_dados):
#...
@property
def formato_linha(self):
# some method
class Registro_C170(BaseModel):
"""
"""
# Atributos
a = CharField()
b = CharField()
reg_c100 = ForeignKeyField(Registro_C100, backref='registros_c170')
@property
def dados(self):
# some property
@dados.setter
def dados(self, novos_dados):
# ...
@property
def formato_linha(self):
# some method
模型_测试:
import unittest, os
from peewee import SqliteDatabase
from modelo_pis_cofins import Registro_0140, Registro_C170, Registro_C100
MODELS = [Registro_0140, Registro_C170, Registro_C100]
# use an in-memory SQLite for tests.
test_db = SqliteDatabase(':memory:')
class TestRegistroC170(unittest.TestCase):
def setUp(self):
# http://docs.peewee-orm.com/en/latest/peewee/database.html#testing-peewee-applications
test_db.bind(MODELS, bind_refs=False, bind_backrefs=False)
test_db.connect()
test_db.create_tables(MODELS)
self.regc170 = Registro_C170()
self.regc170_1 = Registro_C170(a="a", b="b")
self.regc170_1.save() # this raises the errors
self.regc100 = Registro_C100(x="x", y="y")
self.regc100.save() # this raises the errors
def tearDown(self):
test_db.drop_tables(MODELS)
test_db.close()
def test_Registro_C170_atributos(self):
# do some test
def test_Registro_c170_dados(self):
# do some test:
def test_Registro_C170_formato_linha(self):
# do some test
def test_Registro_C170_relacionamentos(self):
# I will test relationships between "Registro_C170" and "Registro_C100"
query = Registro_C100.get(Registro_C100.id == 1)
query.registros_c170
错误:
======================================================================
ERROR: test_Registro_C170_atributos (modelo_pis_cofins_testes.TestRegistroC170)
----------------------------------------------------------------------
Traceback (most recent call last):
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 2640, in execute_sql
cursor.execute(sql, params or ())
sqlite3.IntegrityError: NOT NULL constraint failed: registro_c170.reg_c100_id
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:\Users\vitor.rabelo\Documents\projetos_automatizacao\projeto_efd\processamento_efd\modelo_pis_cofins_testes.py", line 76, in setUp
self.regc170_1.save()
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 5577, in save
pk_from_cursor = self.insert(**field_dict).execute()
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 1574, in inner
return method(self, database, *args, **kwargs)
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 1645, in execute
return self._execute(database)
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 2288, in _execute
return super(Insert, self)._execute(database)
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 2063, in _execute
cursor = database.execute(self)
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 2653, in execute
return self.execute_sql(sql, params, commit=commit)
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 2647, in execute_sql
self.commit()
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 2438, in __exit__
reraise(new_type, new_type(*exc_args), traceback)
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 177, in reraise
raise value.with_traceback(tb)
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 2640, in execute_sql
cursor.execute(sql, params or ())
peewee.IntegrityError: NOT NULL constraint failed: registro_c170.reg_c100_id
======================================================================
ERROR: test_Registro_C170_formato_linha (modelo_pis_cofins_testes.TestRegistroC170)
----------------------------------------------------------------------
Traceback (most recent call last):
File "C:\Users\vitor.rabelo\Documents\projetos_automatizacao\projeto_efd\processamento_efd\modelo_pis_cofins_testes.py", line 68, in setUp
test_db.connect()
File "C:\Users\vitor.rabelo\virtual_enviroments\processamento_efd\lib\site-packages\peewee.py", line 2583, in connect
raise OperationalError('Connection already opened.')
peewee.OperationalError: Connection already opened.
我试过的:
老实说,我知道我唯一可以尝试的是在每个测试方法中创建每个实例,但这正是我想要避免的。
我搜索了“peewee testing”和“peewee unittest”,但没有找到任何有用的东西。Peewee文档只有你展示了如何写的安装和拆卸方法:http://docs.peewee-orm.com/en/latest/peewee/database.html#testing-peewee-applications或如何使用他们的test_utils:HTTP: //docs.peewee-orm.com/en/latest/peewee/playhouse.html#test-utils
ps:这是我的第一个问题,希望它足够清楚:)
好吧,这很尴尬。我意识到我正在保存一个没有值的实例ForeignKeyField
(默认为null=False
)。我需要做的就是允许该字段接受null
值 ( null=True
)。
很抱歉有任何麻烦。
本文收集自互联网,转载请注明来源。
如有侵权,请联系 [email protected] 删除。
我来说两句