我在Windows Phone 8.1应用程序中使用RestSharp。RESTClient实现抛出异常时,服务器返回的代码不同的响应比200维基说,我应该得到的响应与正确的状态码。我想获取响应的内容,因为服务器返回错误消息。
private async Task<T> ExecuteAsync<T>(IRestRequest request)
{
if (!_networkAvailableService.IsNetworkAvailable)
{
throw new NoInternetException();
}
request.AddHeader("Accept", "application/json");
IRestResponse<T> response;
try
{
response = await _client.Execute<T>(request); //here I get exception
}
catch (Exception ex)
{
throw new ApiException();
}
HandleApiException(response);
return response.Data;
}
private void HandleApiException(IRestResponse response)
{
if (response.StatusCode == HttpStatusCode.OK)
{
return;
}
//never reach here :(
ApiException apiException;
try
{
var apiError = _deserializer.Deserialize<ApiErrorResponse>(response);
apiException = new ApiException(apiError);
}
catch (Exception)
{
throw new ApiException();
}
throw apiException;
}
服务器响应样本:
HTTP/1.1 400 Bad Request
Cache-Control: no-cache
Pragma: no-cache
Content-Length: 86
Content-Type: application/json;charset=UTF-8
Expires: -1
Server: Microsoft-IIS/8.0
Access-Control-Allow-Origin: *
X-Powered-By: ASP.NET
Date: Mon, 28 Sep 2015 12:30:10 GMT
Connection: close
{"error":"invalid_token","error_description":"The user name or password is incorrect"}
如果您在Windows Phone 8.1下工作,则使用的是RestSharp Portable(https://github.com/FubarDevelopment/restsharp.portable)(可能)。用这个:
var client = new RestClient();
client.IgnoreResponseStatusCode = true;
这样,您就不会遇到例如404的异常。希望对您有所帮助:)
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