这是我的代码
#course registration
list_courses=[]
for line in open("courses.txt",'r').readlines():
list_courses.append(line.strip())
print ("Gathering course information from file: \n",list_courses)
close("courses.txt")
list_student=[]
for line in open("students.txt",'r').readlines():
list_student.append(line.strip())
print("Here is student info: \n",list_student)
close("students.txt")
当我尝试关闭文件时，这给了我错误。如何关闭，我基本上是在读取文件内容并将它们存储在列表中。现在稍后想要关闭打开的文件。出现错误。
我根据下面的建议编辑了代码。新代码是
list_courses=[]
with open("courses.txt",'r') as myfile1:
list_courses=myfile1.readlines()
list_courses=[x.strip() for x in list_courses]
print ("Gathering course information from file: \n",list_courses)
list_student=[]
with open("students.txt",'r') as myfile1:
list_student=myfile1.readlines()
list_student=[x.strip() for x in list_student]
print("Here is student info: \n",list_student)
Courses.txt 中的信息是
cs101,C programming
cs102,Digital logic and design
cs103,Electrical engineering
cs231,IT networks
cs232,IT Workshop
cs233,IT programming
cs301,Compilers and automata
cs302,Operating Systems
cs303,Networks
cs401,Game Theory
cs402,Systems Programming
cs403,Automata
ec101,Digitization
ec102,Analog cicuit design
ec103,IP Telephony
ec201,Wireless Network
ec202,Microwave engineering
ec203,Antenna
ec301,Maths2
ec302,Theory of Circuits
ec303,PCB design
ec401,PLC programming
ec402,Scada
ec403,VLSI
当我运行代码时，我得到输出
Gathering course information from file:
['cs101,C programming', 'cs102,Digital logic and design', 'cs103,Electrical engineering', 'cs231,IT networks', 'cs232,IT Workshop', 'cs233,IT programming', 'cs301,Compilers and automata', 'cs302,Operating Systems', 'cs303,Networks', 'cs401,Game Theory', 'cs402,Systems Programming', 'cs403,Automata', 'ec101,Digitization', 'ec102,Analog cicuit design', 'ec103,IP Telephony', 'ec201,Wireless Network', 'ec202,Microwave engineering', 'ec203,Antenna', 'ec301,Maths2', 'ec302,Theory of Circuits', 'ec303,PCB design', 'ec401,PLC programming', 'ec402,Scada', 'ec403,VLSI']
而不是我想要的是来自courses.txt第一行的输入cs101进入list_courses[0]和list_courses[1]进行c编程，即list_courses[0]=cs101 list_courses[1]=C编程
所以我尝试了一些方法，其中程序取一行并读取存储该行作为列表元素的行，但是在courses.txt中有一个逗号分隔两个元素，逗号分隔值应该是单独的列表元素。
这对你有用：
students=[]
subject=[]
with open("students.txt","r") as f:
for line in f.readlines():
eachl=line.split(",")
students.append(eachl[0])
subject.append(eachl[1][:-1])
您将获得两个包含学生姓名的列表和另一个包含主题的列表：
学生名单将如下所示：
['cs101', 'cs102', 'cs103', 'cs231', 'cs232', 'cs233', 'cs301', 'cs302', 'cs303', 'cs401', 'cs402', 'cs403', 'ec101', 'ec102', 'ec103', 'ec201', 'ec202', 'ec203', 'ec301', 'ec302', 'ec303', 'ec401', 'ec402', 'ec40`3]
主题列表将如下所示：
['C programming', 'Digital logic and design', 'Electrical engineering', 'IT networks', 'IT Workshop', 'IT programming', 'Compilers and automata', 'Operating Systems', 'Networks', 'Game Theory', 'Systems Programming', 'Automata', 'Digitization', 'Analog cicuit design', 'IP Telephony', 'Wireless Network', 'Microwave engineering', 'Antenna', 'Maths2', 'Theory of Circuits', 'PCB design', 'PLC programming', 'Scada', 'VLSI']
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