我想将这个表的chapter_idand映射到brother_id下面的兄弟和章节表，并分别返回brothername和name字段。使用 js 或 jquery。我正在使用 vuejs 返回分钟数组作为计算属性。见下文。
在sql它是这样的
select brothername from brothers where minute.brother_id = brothers.id...然后将兄弟名称设置为新值brother_id
同样的事情也适用于chapter_id：
select brothername from brothers where minute.brother_id = brothers.id...然后将兄弟名称设置为新值brother_id
结果数组或对象应该是：
预期数组[
{
"location":"UCLA",
"chapter_id":"Beta",
"brother_id":"Golpher",
"created_at":"2008-05-15 22:23:00",
"status":"Approved"
},
{ ... },
{
"location":"John's Deli",
"chapter_id":"Beta", notice the change in the array based on the ids
"brother_id":"Sheera", notice the change in the array based on the ids
"created_at":"2008-05-15 22:23:00",
"status":"Approved"
}
]
[
{
"location":"UCLA",
"chapter_id":2,
"brother_id":1,
"created_at":"2008-05-15 22:23:00",
"status":"Approved"
},
{ ... },
{
"location":"John's Deli",
"chapter_id":2,
"brother_id":4,
"created_at":"2008-05-15 22:23:00",
"status":"Approved"
}
]
[
{
"id":1,
"letter_representation":"A",
"name":"Alpha",
"founded_at":"UCLA",
...
},
{ ... }
]
[
{
"id":1,
"profile_id":1,
"chapter_id":1,
"brothername":"Golpher",
"firstname":"Jack",
...
},
{ ... },
{
"id":4,
"profile_id":4,
"chapter_id":1,
"brothername":"Sheera",
"firstname":"Jake",
...
}
]
computed: {
brothers () {
return this.$store.state.brothers
},
chapters () {
return this.$store.state.chapters
},
minutes () {
return this.$store.getters.model
}
},
我假设您不想使用此操作改变原始数组中的对象。
注意您可能希望处理相应表中不存在brother_id或chapter_id不存在的情况。在下面的示例中，它只是将属性值设置为undefined
const minutesTable = [{
"location": "UCLA",
"chapter_id": 2,
"brother_id": 1,
"created_at": "2008-05-15 22:23:00",
"status": "Approved"
}, {
"location": "John's Deli",
"chapter_id": 2,
"brother_id": 4,
"created_at": "2008-05-15 22:23:00",
"status": "Approved"
}]
const chapterTable = [{
"id": 1,
"letter_representation": "A",
"name": "Alpha",
"founded_at": "UCLA",
}]
const brotherTable = [{
"id": 1,
"profile_id": 1,
"chapter_id": 1,
"brothername": "Golpher",
"firstname": "Jack",
}, {
"id": 4,
"profile_id": 4,
"chapter_id": 1,
"brothername": "Sheera",
"firstname": "Jake",
}]
// your result
const result = minutesTable.map(m => {
const brother = brotherTable.find(b => b.id === m.brother_id)
const chapter = chapterTable.find(c => c.id === m.chapter_id)
return Object.assign({}, m, {
brother_id: brother && brother.brothername,
chapter_id: chapter && chapter.name,
})
})
console.log(result)本文收集自互联网，转载请注明来源。
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