如何在不同的上下文中使用变量？

小黄人

    private void browsebtn_Click(object sender, EventArgs e)
    {
        OpenFileDialog fdlg = new OpenFileDialog();
        fdlg.Title = "Select Song";
        fdlg.InitialDirectory = @"c:\";
        fdlg.Filter = "All files (*.*)|*.*|All files (*.*)|*.*";
        fdlg.FilterIndex = 2;
        fdlg.RestoreDirectory = true;
        if (fdlg.ShowDialog() == DialogResult.OK)
        {
            filedialoglbl.Text = fdlg.FileName;
        }
    }

    private void runbtn_Click(object sender, EventArgs e)
    {
        var Path = fdlg.FileName;
        var pi = new System.Diagnostics.ProcessStartInfo(Path)
        {
            Arguments = Path.GetFileName(Path),
            UseShellExecute = true,
            WorkingDirectory = Path.GetDirectoryName(Path),
            FileName = "C:\\relax.exe",
            Verb = "OPEN"
        };
        System.Diagnostics.Process.Start(pi);
    }
}

如您所见，我正在尝试选择一个文件并使用该文件运行另一个程序，但我不想使用 Windows 默认值。

我的错误在

var Path = fdlg.FileName;

问题是 fdlg 不在同一上下文中，我需要使用之前选择的目录，有关如何执行此操作的任何想法？

从我试过的答案来看：

    private OpenFileDialog fdlg = new OpenFileDialog();
    private void browsebtn_Click(object sender, EventArgs e)
    {
        fdlg.Title = "Select Song";
        fdlg.InitialDirectory = @"c:\";
        fdlg.Filter = "All files (*.*)|*.*|All files (*.*)|*.*";
        fdlg.FilterIndex = 2;
        fdlg.RestoreDirectory = true;
        if (fdlg.ShowDialog() == DialogResult.OK)
        {
            filedialoglbl.Text = fdlg.FileName;
        }
    }

    private void runbtn_Click(object sender, EventArgs e)
    {
        var Path = fdlg.Text;
        var pi = new System.Diagnostics.ProcessStartInfo(Path)
        {
            Arguments = Path.GetFileName(Path),
            UseShellExecute = true,
            WorkingDirectory = Path.GetDirectoryName(Path),
            FileName = "C:\\relax.exe",
            Verb = "OPEN"
        };
        System.Diagnostics.Process.Start(pi);
    }

并且我收到一条错误消息，指出“OpenFileDialog”没有“Text”的定义或扩展方法以及类中的行：

private OpenFileDialog fdlg = new OpenFileDialog();

我收到一个新错误，指出“GetFileName”和“GetDirectoryName”在“string”中没有定义或扩展方法

编辑

我将路径重命名为目录但同样的错误

        private void runbtn_Click(object sender, EventArgs e)
    {
        var directory =filedialoglbl.Text;
        var pi = new System.Diagnostics.ProcessStartInfo(directory)
        {
            Arguments = directory.GetFileName(directory),
            UseShellExecute = true,
            WorkingDirectory = directory.GetDirectoryName(directory),
            FileName = "C:\\relax.exe",
            Verb = "OPEN"
        };
        System.Diagnostics.Process.Start(pi);
    }

阿尔法75

您在 runbtn_Click 方法中使用对话框仅用于FileName. 您将其保存到名为的标签中filedialoglbl.Text。用它。

private void browsebtn_Click(object sender, EventArgs e)
{
    OpenFileDialog fdlg = new OpenFileDialog();
    fdlg.Title = "Select Song";
    fdlg.InitialDirectory = @"c:\";
    fdlg.Filter = "All files (*.*)|*.*|All files (*.*)|*.*";
    fdlg.FilterIndex = 2;
    fdlg.RestoreDirectory = true;
    if (fdlg.ShowDialog() == DialogResult.OK)
    {
        filedialoglbl.Text = fdlg.FileName;
    }
}

private void runbtn_Click(object sender, EventArgs e)
{
    var path = filedialoglbl.Text;
    var pi = new System.Diagnostics.ProcessStartInfo(path)
    {
        Arguments = Path.GetFileName(path),
        UseShellExecute = true,
        WorkingDirectory = Path.GetDirectoryName(path),
        FileName = "C:\\relax.exe",
        Verb = "OPEN"
    };
    System.Diagnostics.Process.Start(pi);
}

编辑

您不能使用大写的 Path ，因为您正在隐藏 Path 类并且您不能使用它们的方法。

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