我在做一个项目,我不得不从二维数组做一个矩阵。一的要求是隐蔽3×4 2D阵列(具有值存储在)至6X2 2D阵列(具有相同的值)?
public int[][] covertMatrix(int[][] ma, int r, int c) {
rw = r;
col = c;
this.ma = new int[rw][col];
for (int i = 0; i < rw; i++) {
for (int j = 0; j < col; j++) {
ma[i][j] = ma[i][j];
}
}
return ma;
}
我试过这个代码,它重塑了数组,但只打印零的二维数组。
你有什么是3x4的像一开始矩阵
+--+--+--+--+
|01|02|03|04|
+--+--+--+--+
|05|06|07|08|
+--+--+--+--+
|09|10|11|12|
+--+--+--+--+
要在一个6X2矩阵转换一样
+--+--+
|01|02|
+--+--+
|03|04|
+--+--+
|05|06|
+--+--+
|07|08|
+--+--+
|09|10|
+--+--+
|11|12|
+--+--+
要做到这一点,显然tab1[i][j] = tab2[i][j]
是行不通的。您需要将两个数组之间进行转换的地址。乍一看,使用该行的取模和分裂的其余为山坳会做的伎俩。
就像是
public static void main(String[] args) {
int[][] tab1 = new int[][]{{1,2,3,4},{5,6,7,8},{9,10,11,12}};
System.out.println(Arrays.deepToString(tab1));
System.out.println("---------------------------");
int size = tab1.length * tab1[0].length;
for(int i = 1; i <= size; i++){
int j = size % i;
if(j == 0){
convert(tab1, i, size/i);
}
}
}
private static void convert(int[][] tab1, int row, int col) {
System.out.println(String.format("converting to %dx%d", row, col));
int[][] tab2 = new int[row][col];
for(int i = 0; i < row; i++){
for(int j = 0; j < col; j++){
int index = i*col + j;
int newRow = index / tab1[0].length;
int newCol = index % tab1[0].length;
tab2[i][j] = tab1[newRow][newCol];
}
}
System.out.println(Arrays.deepToString(tab2));
System.out.println("---------------------------");
}
这给输出
[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
---------------------------
converting to 1x12
[[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]]
---------------------------
converting to 2x6
[[1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12]]
---------------------------
converting to 3x4
[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
---------------------------
converting to 4x3
[[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]
---------------------------
converting to 6x2
[[1, 2], [3, 4], [5, 6], [7, 8], [9, 10], [11, 12]]
---------------------------
converting to 12x1
[[1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12]]
---------------------------
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