我在从同步ajax调用返回值时遇到一些问题。我要返回的值是我为服务器响应创建的类。
这是AJAX代码：
function webRequest(file, data) {
return $.ajax({
url: "http://xxx.xx.xx.xxxx/xxxxx/"+file,
type: "POST",
data: data,
asynch: false,
error: function(jqXHR, textStatus, errorThrown){
return new ServerResponse(false, errorThrown);
},
success: function(data, textStatus, jqXHR){
return new ServerResponse(true, data);
},
timeout: 7500
});
}
这是ServerResponse.js
var success = false;
var text = null;
var ServerResponse = function(success, text) {
this.success = success;
this.text = text || null;
};
ServerResponse.prototype.isSuccessful = function() {
return this.success;
};
ServerResponse.prototype.getData = function() {
return this.text;
};
的返回值webRequest(..)如下：
Object {readyState: 1, getResponseHeader: function, getAllResponseHeaders: function, setRequestHeader: function, overrideMimeType: function…}abort: function ( statusText ) {always: function () {complete: function () {done: function () {error: function () {fail: function () {getAllResponseHeaders: function () {getResponseHeader: function ( key ) {overrideMimeType: function ( type ) {pipe: function ( /* fnDone, fnFail, fnProgress */ ) {progress: function () {promise: function ( obj ) {readyState: 0responseText: ""setRequestHeader: function ( name, value ) {state: function () {status: 0statusCode: function ( map ) {statusText: "error"success: function () {then: function ( /* fnDone, fnFail, fnProgress */ ) {__proto__: Object VM2324 controllers.js:48
如何返回ServerResponse从ajax调用中创建的实例？
@fuyushimoya的答案几乎就在那里，只需从包装函数返回新实例化的服务器响应对象。
function webRequest(file, data) {
var serverResponse;
$.ajax({
url: "http://xxx.xx.xx.xxxx/xxxxx/"+file,
type: "POST",
data: data,
async: false,
error: function(jqXHR, textStatus, errorThrown){
serverResponse = new ServerResponse(false, errorThrown);
},
success: function(data, textStatus, jqXHR){
serverResponse = new ServerResponse(true, data);
},
timeout: 7500
});
return serverResponse;
}
这样你可以做
var sr = webRequest('some/file', someData);
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我来说两句