有一个列表包含子列表,如下所示:
country_list = ['pakistan', 'india', 'iran', 'china', 'afghanistan', ['pakistan', 'iran', 'india']]
输出应该是: ['pakistan', 'india', 'iran']
主列表中可以有多个子列表,例如:
countries = ['pakistan', 'india', 'iran', 'china', 'afghanistan', ['pakistan', 'india'], ['china', 'pakistan']]
输出应该是: ['pakistan', 'india', 'china']
我需要一个通用函数,它返回一个包含重复项的列表。
由于@Alex 提到了解“扁平列表”,我想出了解决方案:
假设有一个列表列表或一个包含子列表的列表:
import collections
countries = ['pakistan', 'india', 'iran', 'china', 'afghanistan', ['pakistan', 'india'], ['china', 'pakistan']]
def flatten_list(c_list):
"""
function to convert list of lists into flat list.
"""
result = []
for country in c_list:
if isinstance(country, collections.Iterable) and not isinstance(country, (str, bytes)):
result.extend(flatten_list(country))
else:
result.append(country)
return result
def list_of_duplicates(flat_list):
"""
function to get duplicate entries and removing single entries
"""
new_list = flat_list
for e in set(new_list):
new_list.remove(e)
return list(set(new_list))
result = list_of_duplicates(flatten_list(countries)) #desired result
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