Apache Camel 超时同步路由

维克多·特里佩诺

我正在尝试使用 Apache Camel 构建一个带超时的同步路由，但我在框架中找不到任何可以解决它的内容。所以我决定为我建立一个流程。

public class TimeOutProcessor implements Processor {

private String route;
private Integer timeout;

public TimeOutProcessor(String route, Integer timeout) {
    this.route = route;
    this.timeout = timeout;
}


@Override
public void process(Exchange exchange) throws Exception {
    ExecutorService executor = Executors.newSingleThreadExecutor();

    Future<Exchange> future = executor.submit(new Callable<Exchange>() {

        public Exchange call() {
            // Check for field rating

            ProducerTemplate producerTemplate = exchange.getFromEndpoint().getCamelContext().createProducerTemplate();
            return producerTemplate.send(route, exchange);
        }
    });
    try {
        exchange.getIn().setBody(future.get(
                timeout,
                TimeUnit.SECONDS));
    } catch (TimeoutException e) {
        throw new TimeoutException("a timeout problem occurred");
    }
    executor.shutdownNow();
}

我这样称呼这个过程：

.process(new TimeOutProcessor("direct:myRoute",
                Integer.valueOf(this.getContext().resolvePropertyPlaceholders("{{timeout}}")))

我想知道我的方法是否是推荐的方法，如果不是，构建超时同步路由的最佳方法是什么？

维克多·特里佩诺

我要感谢回答我的人。

这是我的最终代码：

public class TimeOutProcessor implements Processor {

private String route;
private Integer timeout;

public TimeOutProcessor(String route, Integer timeout) {
    this.route = route;
    this.timeout = timeout;
}


@Override
public void process(Exchange exchange) throws Exception {
    Future<Exchange> future = null;
    ProducerTemplate producerTemplate = exchange.getFromEndpoint().getCamelContext().createProducerTemplate();
    try {

        future = producerTemplate.asyncSend(route, exchange);
        exchange.getIn().setBody(future.get(
                timeout,
                TimeUnit.SECONDS));
        producerTemplate.stop();
        future.cancel(true);
    } catch (TimeoutException e) {
        producerTemplate.stop();
        future.cancel(true);
        throw new TimeoutException("a timeout problem occurred");
    }

}
}

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