如何在java中找到最接近零的五个输入数字

仅添加

我是java编程的新手。有人可以教如何使用Scanner. 示例用户插入第一个 number=-4，第二个 number=3，依此类推更大的 numbers，那么接近于零的答案是3。

下面是代码

import java.util.Scanner;

class NearZero {

public static void main(String[]args) {

    Scanner scn = new Scanner(System.in);

    int firstNumber,secondNumber,thirdNumber,fourNumber,fiveNumber;
    int nearNumberZero;


    System.out.println("Enter number 1");
    firstNumber = scn.nextInt();
    System.out.println("Enter number 2");
    secondNumber = scn.nextInt();
    System.out.println("Enter number 3");
    thirdNumber = scn.nextInt();
    System.out.println("Enter number 4");
    fourNumber = scn.nextInt();
    System.out.println("Enter number 5");
    fiveNumber = scn.nextInt();

    nearNumberZero =

    System.out.println("The number near zero 0 is");
}

}

普拉文

您可以将输入的号码保留在 a 中，loop因为操作是相同的，并且如下所示，

import java.util.Scanner;

class NearZero {

    public static void main(String[] args) {
        Scanner scn = new Scanner(System.in);
        int number;
        int nearNumberZero = 0;

        for (int i = 1; i <= 5; i++) {
            System.out.println("Enter number " + i);
            number = scn.nextInt();
            // by default first is nearest or it will check for other numbers
            if (i == 1 || Math.abs(number) < Math.abs(nearNumberZero))
                nearNumberZero = number;
        }
        System.out.println("The number near zero 0 is - " + nearNumberZero);
        scn.close();//prefer closing your resources (with a try-finally preferrable)
    }

}

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