我有两个数组，一个是字符串数组，另一个是['security', 'hobbies']对象数组[{name: 'randome', category: 'hobbies'}, {name: 'randome', category: 'randome'}, {name: 'randome', category: 'randome'}, {name: 'randome', category: 'security'}]，我试图循环这两个数组和splice所有那些与第一个数组上的类别不匹配但总是只得到的对象循环中的一个元素。
for (let i = 0; i < searchparam.category.length; i++) {
for (let j = 0; j < validapps.length; j++) {
let match: boolean = false;
if (validapps[j].category === searchparam.category[i]) {
console.log(validapps[j])
match = true;
return;
}
if (!match) {
validapps.splice(j, 1);
j--;
}
}
}
循环后我应该得到 2 个或更多元素，但总是只得到一个。结果数据总是一个元素。
_id: "598c69259fe2ff5fd0432396"
active: true
app_language: Array [ "DE" ]
application_code: "ASF"
blacklist: Array []
category: "utilities"
comments: ""
contacts: Array [ "598c40cf0f05ba5d0c5da01a", "598c66d59fe2ff5fd043238a", "59ce05683d7daf37702c1fc1", … ]
id: "598c69259fe2ff5fd0432396"
image: ""
insertDate: "2017-08-10T14:09:41.189Z"
name: "Alpha SSD Fresh"
os: Array [ {…} ]
updateDate: "2017-08-10T14:09:41.608Z"
或者你可以使用 filter
var arr = [{name: 'randome', category: 'hobbies'}, {name: 'randome', category: 'randome'}, {name: 'randome', category: 'randome'}, {name: 'randome', category: 'security'}];
var validItems = ['security', 'hobbies'];
arr = arr.filter( s => validItems.indexOf( s.category ) != -1 ); //only those items will be passed through which have valid categories
或者
arr = arr.filter( s => validItems.includes( s.category ) ); //only those items will be passed through which have valid categories
本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句