尽管我对Web开发的知识不足，但我一直在尝试解决数小时。情况如下：
另一个网站具有一个脚本，他们可以通过以下方式获取信息：
var url = "numbers.php";
parameters = "scoreid=" + document.getElementById('whatscore').value;
parameters += "&num=" + document.getElementById('num1b1').value;
xmlhttp2=GetXmlHttpObject();
if (xmlhttp2==null) {
alert ("Your browser does not support XMLHTTP!");
return;
}
xmlhttp2.onreadystatechange = function() {
if (xmlhttp2.readyState==4) {
scorespot.innerHTML=xmlhttp2.responseText; // load
setScores(document.getElementById('gradelvl').value); // set
document.getElementById('submitscorebtn').style.display="none";
}
}
xmlhttp2.open("POST",url,true);
xmlhttp2.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xmlhttp2.setRequestHeader("Content-length", parameters.length);
xmlhttp2.setRequestHeader("Connection", "close");
xmlhttp2.send(parameters);
我曾尝试做同样的事情，尽管尝试时会出现跨域错误。我知道他们是用jsonp和其他方法实现的方式，尽管我不知道从何开始。
当我尝试直接从他们的页面请求信息时，numbers.php页面，例如example.com/numbers.php?scoreid=131&num=41。我总是返回“错误：参数语法错误”。
有人可以告诉我如何解决此问题吗？我只非常了解PHP和Javascript，对Ajax和其他东西或外部库没有很好的了解。
我感谢所有帮助！注意：我没有访问网络服务器。
如果您无权访问服务器配置，并且不控制外部php脚本（假设未将其设置为充当反向代理），那么您绝对不能为此使用独立的javascript解决方案。
相反，您必须从您自己的本地php脚本发出外部请求。然后，您将从Ajax调用本地php脚本，这将起作用，因为您正在访问本地文件，因此不会违反CORS。
这是通过本地PHP脚本进行Ajax调用的示例。
想象一个场景，允许用户查找相册名称。用户输入歌曲的名称和艺术家。您向第3方api发送请求，然后通过JavaScript警报通知将响应返回给用户。对于此示例，假设用户输入“ Black”和“ Pearl Jam”作为歌曲和歌手姓名
Ajax POST到带有HTML示例的本地PHP脚本：
<html>
<head>
<!-- Load jQuery Library from Google -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"> </script>
</head>
<body>
<h1> Ajax to local PHP Script Example: </h1>
<form id="getArtist">
Artist: <input type="text" placeholder="Pearl Jam">
Song: <input type="text" placeholder="Black">
<input type="submit" value="Click Here to Active Ajax Call">
</form>
</body>
</html>
<script type='text/javascript'>
$("#getArtist").submit(function(event) { //Listen to when the Submit is pressed
event.preventDefault(); //Stop the submit from actually performing a submit
$.post("local_script.php", { song: "Black", artist: "Pearl Jam", dataType: "json"}) //prepare and execute post
.done(function(response) { //Once we receive response from PHP script
//Do something with the response:
alert("The album name is: " +response);
//Look into JSON.parse and JSON.stringify for accessing data
});
});
</script>
PHP GET
<?php
$url = 'http://api.music.com/album';
$song = urlencode($_GET['song'])); //Need to url encode
$artist = urlencode($_GET['artist']); //Need to url encode
$response = file_get_contents($url .'?song=' .$song .'&artist=' .$artist);
//**The url looks like http://api.music.com/album?song=Black&artist=Pearl+Jam
//** For purposes of this demo, we will manually assume the JSON response from the API:
$response = '{ "album": "Ten" }'; //(Raw JSON returned by API)
echo $response; //Return the response back to AJAX, assuming it is already returned as JSON. Else encode it json_encode($response)
PHP POST（使用curl）
<?php
$url = 'http://api.music.com/album';
$song = urlencode($_GET['song'])); //Need to url encode
$artist = urlencode($_GET['artist']); //Need to url encode
//$headers = array("Key: " ."Value","Key: " ."Value", //Set any headers, if required.
$post = 'song=' .$song .'&artist=' .$artist; //Prepare Post parameters
/* Configure Curl */
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); //Allow music api to send response
curl_setopt($ch, CURLOPT_POST, 1); //Signifyd that we are doing a POST request
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
//curl_setopt($curl, CURLOPT_HTTPHEADER, $header); //Only if you need to send headers
/* Get Response */
$response = curl_exec($ch);
//** For purposes of this demo, we will manually assume the JSON response from the API:
$response = '{ "album": "Ten" }'; //(Raw JSON returned by API)
echo $response; //Send response back to Ajax, assuming it was already returned in JSON. Else encode it.
有关Ajax请求的更多信息：
https : //api.jquery.com/jquery.get/
https://api.jquery.com/jquery.post/
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