好的，您可能会知道，但是，我对MySQL和PHP还是很陌生，并且遇到了问题。在connect.php连接到服务器的my中，我不知道我的密码和用户名是否与港口是正确的。现在说8080端口的原因是因为我的其他Web开发程序之一正在使用80端口，所以我进入了Apache文件并更改为port，所以现在登录phpMyAdmin时必须输入localhost:8080。我不知道这是否与mysql_connect，也检查了phpMyAdmin并说我的用户名是root，密码为空。空密码会引起混乱MySQL_connect()吗？谢谢，这是代码：
connect.php：
<?php
//This file allows me to easily connect to my database
mysql_connect("localhost:8080", "root", "");//connects to database, params are ("servername", "username", "password");
mysql_select_db("membersystem");//selects the table from db
?>
login.php：
<?php
error_reporting (E_ALL ^ E_NOTICE);//saves us from getting undefined index error
session_start();//makes it a sesion based system
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Login</title>
</head>
<body>
<!--the action='./login.php' tells the page where its gonna send the info, and the method='post' makes it so it dosent show the users personal info -->
<?php
$form = "<form action='./login.php' method='post'>
<table>
<tr>
<td>Username</td>
<td><input type='text' name='user'/></td>
</tr>
<tr>
<td>Password</td>
<td><input type='password' name='password'/></td>
</tr>
<tr>
<td></td>
<td><input type='submit' name='loginbtn' value='Login'/></td>
</tr>
</table>
</form>";
if($_POST['loginbtn']){//if loginbtn pressed
$user = $_POST['user'];//gets the username from text field from the form above
$password = $_POST['password'];//gets the password from text field from the form above
if($user){//checks if the username field from the form has been filled out
if($password){//checks if the password field from the form has been filled out
require("connect.php");//connects to db through connect.php
$password = md5(md5("gshgrYY665f".$password."gr76TH967G"));//encrypts the password
//echo "$password"; echos the hash for password (5f8b1a8d8f2471a2c7c17e0058873447 )
$query = mysql_query("SELECT * FROM users WHERE username='$user' ");//checks if the username is found in database
$numrows = mysql_num_rows($query);
if($numrows == 1){
$row = mysql_fetch_assoc($query);//gets the query associated with the php
$dbid = $row['id'];//gets the id from db
$dbuser = $row['username'];//gets the username from db
$dbpass = $row['password'];//gets the password from db
$dbactive= $row['active'];//gets the active value from db
if($password == $dbpass){
if($dbactive == 1){
//sets session info
$_SESSION['userid'] = $dbid;
$_SESSION['username'] = $dbuser;
echo "you have been logged in as <b>$dbuser</b>. <a href='./member.php'>Click here</a> to go to member page";
}
else
echo "You must activate your account to login. $form";
}
else
echo "You didnt enter the right pass. $form";
}
else
echo "The username you entered was not found. $form";
mysql_close();//closes connection
}
else
echo "You must enter your password. $form";
}
else
echo "You must enter your username. $form";
}
else
echo $form;
?>
</body>
</html>
您不需要使用8080简单使用，localhost因为该端口号与mysql不相关，但与Web服务器相关。为了只访问网络服务器，您需要像localhost:8080/project-name/
并且不要使用mysql_*方法。将来会失望的。用mysqli
$con = new mysqli("localhost","root","","membersystem") or die('Connection failed');
$result = $con->query("Your query here");
否则您可以在mysqli_*函数中使用相同的过程方法。但是我更喜欢与面向对象的php一起使用。
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我来说两句