我想覆盖 account.invoice 模型的 unlink 方法。
目前这种方法是:
@api.multi
def unlink(self):
for invoice in self:
if invoice.state not in ('draft', 'cancel'):
raise UserError(
_('You cannot delete an invoice which is not draft or cancelled. You should refund it instead.'))
elif invoice.move_name:
raise UserError(_(
'You cannot delete an invoice after it has been validated (and received a number). You can set it back to "Draft" state and modify its content, then re-confirm it.'))
return super(AccountInvoice, self).unlink()
如果已分配 move_name(即为此发票指定了有效序列),则它不会让您删除发票。虽然这是一个完美无瑕的会计规则,但它反映了对某些业务的现实世界运营的了解不足,您实际上需要删除发票。
所以我想允许用户删除最后一张发票,即使它被提出。
为此,需要以编程方式(在 python 擦除方法中)执行以下操作:
有人可以帮助强调如何实现这三个步骤(特别是第一个步骤)。
谢谢,
这是您的第一个查询的答案:
查询:如何识别适用于该发票的序列号?
代码:
@api.multi
def unlink(self):
for invoice in self:
if invoice.state not in ('draft', 'cancel'):
raise UserError(_('You cannot delete an invoice which is not draft or cancelled. You should refund it instead.'))
elif invoice.move_name:
print "movename", invoice.move_name
if invoice.journal_id.sequence_id:
sequence_id = invoice.journal_id.sequence_id.id
print sequence_id
raise UserError(_('You cannot delete an invoice after it has been validated (and received a number). You can set it back to "Draft" state and modify its content, then re-confirm it.'))
return super(AccountInvoice, self).unlink()
我对你的第二和第三个问题有点困惑,因为,考虑到有 5 张发票已验证/处于打开状态,并且你想删除invoice no:3
. 因此,根据您的要求,您将检查 move_name 的值是否与标识序列生成的最后一个值匹配,如果匹配,您将从1
序列的 next_value 中减去。
因此,序列的 next_value 将成为5
,当您创建另一个发票时,序列号将被复制,因为invoice no:5
这将违反序列的唯一约束。
如果您希望您的用户只删除最后创建的发票,那么没问题。
所以想一想,希望我的回答对你有所帮助。
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