如何在不显示任何 if else 语句的情况下打印数组数据

Xaxxis 发表于 Dev

西西斯

我的讲义中有以下示例代码。在我的代码中，如果您尝试直接打印一个，您会得到与我想要的不匹配的输出。如何打印我刚刚选择的汽车清单。不显示任何其他行。但如果输入小于 1 且大于 3，则显示错误消息

  package scanner1;
  import java.util.Scanner;
  public class Scanner1 {
  public static void main(String[] args) {
  Scanner scan = new Scanner(System.in);

  int carSelect;
  int [] noNumb = {1,2,3};
  String [] carList = {"Lexus","Bugati","McLaren"};

  System.out.println("================ Car List ================");
    for (int i = 0; i < noNumb.length; i++) {
        System.out.println(noNumb [i]+". "+carList[i]);
    }     
     System.out.println(" ");
     System.out.print("Choose your car : ");
     carSelect = scan.nextInt ();
     loop:
     for (int i=0; i<noNumb.length; i++){
     if(carSelect == noNumb [i]){
         System.out.println("Great you choose " +carList[i]);
         break;
    }else if (carSelect <= noNumb[i]){
         System.out.println("Your input is less than 1 ");  
        break;
    } else {
         System.out.println("Wrong input ");

    }
    }
} }

输出：

 ================ Car List ================
 1. Lexus
 2. Bugati
 3. McLaren

 Choose your car : 3
 Wrong input 
 Wrong input 
 Great you choose McLaren
 BUILD SUCCESSFUL (total time: 1 second)

真相

从你的问题来看，我认为这就是你要找的：

if (carSelect < 1){
     System.out.println("Your input is less than 1 ");  
} else if (carSelect > 3) {
     System.out.println("Wrong input ");
} else {   
   //valid input, let us check the car selected
   System.out.println("Great you choose " +carList[carSelect]);
}

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