我在PostgreSQL数据库上有两个表,合同和付款。一份合同完成了多次付款。
我有以下两个模型:
module.exports = function(sequelize, DataTypes) {
var contracts = sequelize.define('contracts', {
id: {
type: DataTypes.INTEGER,
autoIncrement: true
}
}, {
createdAt: false,
updatedAt: false,
classMethods: {
associate: function(models) {
contracts.hasMany(models.payments, {
foreignKey: 'contract_id'
});
}
}
});
return contracts;
};
module.exports = function(sequelize, DataTypes) {
var payments = sequelize.define('payments', {
id: {
type: DataTypes.INTEGER,
autoIncrement: true
},
contract_id: {
type: DataTypes.INTEGER,
},
payment_amount: DataTypes.INTEGER,
}, {
classMethods: {
associate: function(models) {
payments.belongsTo(models.contracts, {
foreignKey: 'contract_id'
});
}
}
});
return payments;
};
我想对每个合同的所有付款进行汇总,并使用以下功能:
models.contracts.findAll({
attributes: [
'id'
],
include: [
{
model: models.payments,
attributes: [[models.sequelize.fn('sum', models.sequelize.col('payments.payment_amount')), 'total_cost']]
}
],
group: ['contracts.id']
})
但它生成以下查询:
SELECT "contracts"."id", "payments"."id" AS "payments.id", sum("payments"."payment_amount") AS "payments.total_cost"
FROM "contracts" AS "contracts"
LEFT OUTER JOIN "payments" AS "payments" ON "contracts"."id" = "payments"."contract_id" GROUP BY "contracts"."id";
我不要求选择payments.id,因为我必须将其包括在我的汇总或按功能分组中,如错误消息中所述:
可能未处理的SequelizeDatabaseError:错误:列“ payments.id”必须出现在GROUP BY子句中或在聚合函数中使用
我在这里想念什么吗?我正在关注这个答案,但即使到那里我也不清楚SQL请求如何有效。
此问题已在Sequelize 3.0.1中修复,所包含模型的主键必须用
attributes: []
并且聚合必须在主模型上完成(此github问题中的信息)。
因此,对于我的用例,代码如下
models.contracts.findAll({
attributes: ['id', [models.sequelize.fn('sum', models.sequelize.col('payments.payment_amount')), 'total_cost']],
include: [
{
model: models.payments,
attributes: []
}
],
group: ['contracts.id']
})
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