评估作业时出现语法错误

像素

由于某种原因,当我跑步时

import sys
from fractions import Fraction
for i, j in zip(["a","b","c","d","e","f"], range(1,6)):
    eval("{0} = int(sys.argv[{1}])".format(i, j))
if a*d != c*b:
    x = (e*d-b*f)/(a*d-c*b) 
    y = (a*f-c*e)/(a*d-c*b)
    print "x = ", x , ", y = ", y
elif e*d-b*f == 0 and a*f-e*c == 0:
    print "Infinite solutions"
    print "Slope = ", Fraction(-a,b), ", Y-Intercept = ", Fraction(e,b)
else:
    print "No solution"

使用python2 py.py 1 3 3 9 5 15,它给我以下错误

Traceback (most recent call last):
  File "py.py", line 4, in <module>
    eval("{0} = int(sys.argv[{1}])".format(i, j))
  File "<string>", line 1
    a = int(sys.argv[1])
      ^
SyntaxError: invalid syntax

有什么想法为什么会这样?我确定这是有效的语法,但也许eval搞砸了?

内德·巴切尔德

这是的不必要使用eval您的代码:

for i, j in zip(["a","b","c","d","e","f"], range(1,6)):
    eval("{0} = int(sys.argv[{1}])".format(i, j))

可以更好地表示为:

a, b, c, d, e, f = map(int, sys.argv[1:7])

或为:

a, b, c, d, e, f = (int(x) for x in sys.argv[1:7])

[请注意,原始代码的范围错误,应为range(1,7)]

本文收集自互联网,转载请注明来源。

如有侵权,请联系 [email protected] 删除。

编辑于
0

我来说两句

0 条评论
登录 后参与评论

相关文章