我有我的初步声明，即：
SELECT TEAM.ID PKEY_SRC_OBJECT,
TEAM.MODF_DAT UPDATE_DATE,
TEAM.MODF_USR UPDATED_BY,
PERSO.FIRST_NAM FISRT_NAME
FROM TEAM
LEFT OUTER JOIN PERSO ON (TEAM.ID=PERSO.TEAM_ID)
我想计算一些“标志”并在我的初始语句中返回它们。有 3 个标志可以这样计算：
1) 标记 ISMASTER：
SELECT Count(*)
FROM TEAM_TEAM_REL A, TEAM B
WHERE B.PARTY_PTY_ID = A.RLTD_TEAM_ID
AND CODE = 'Double';
2) 标记ISAGENT：
SELECT Count(*)
FROM TEAM_ROL_REL A, TEAM B
WHERE B.PARTY_PTY_ID = A.TEAM_ID;
3) 标记 NUMPACTS：
SELECT Count(*)
FROM TEAM_ROL_REL A,
TEAM_ROL_POL_REL B,
PERSO_POL_STA_REL C,
TEAM D
WHERE A.ROL_CD IN ('1','2')
AND A.T_ROL_REL_ID = B.P_ROL_REL_ID
AND B.P_POL_ID = C.P_POL_ID
AND C.STA_CD = 'A'
AND D.PARTY_PTY_ID = A.TEAM_ID;
为了实现这一目标，我更新了我的初始声明，如下所示：
WITH ABC AS (
SELECT TEAM.ID PKEY_SRC_OBJECT,
TEAM.MODF_DAT UPDATE_DATE,
TEAM.MODF_USR UPDATED_BY,
PERSO.FIRST_NAM FISRT_NAME
FROM TEAM
LEFT OUTER JOIN PERSO ON (TEAM.ID=PERSO.TEAM_ID)
)
SELECT ABC.*, MAST.ISMASTER, AGENT.ISAGENT, PACTS.NUMPACTS FROM ABC
LEFT OUTER JOIN (
select
RLTD_TEAM_ID,
Count(RLTD_TEAM_ID) OVER (PARTITION BY RLTD_TEAM_ID) as ISMASTER
FROM TEAM_TEAM_REL
WHERE CODE = 'Double'
) MAST
ON ABC.PKEY_SRC_OBJECT = MAST.RLTD_TEAM_ID
LEFT OUTER JOIN (
select
TEAM_ID,
Count(TEAM_ID) OVER (PARTITION BY TEAM_ID) as ISAGENT
FROM TEAM_ROL_REL
) AGENT
ON ABC.PKEY_SRC_OBJECT = AGENT.TEAM_ID
LEFT OUTER JOIN (
select
TEAM_ID,
Count(TEAM_ID) OVER (PARTITION BY TEAM_ID) as NUMPACTS
FROM TEAM_ROL_REL, TEAM_ROL_POL_REL, PERSO_POL_STA_REL
WHERE TEAM_ROL_REL.ROL_CD IN ('1','2')
AND TEAM_ROL_REL.T_ROL_REL_ID = TEAM_ROL_POL_REL.P_ROL_REL_ID
AND TEAM_ROL_POL_REL.P_POL_ID = PERSO_POL_STA_REL.P_POL_ID
AND PERSO_POL_STA_REL.STA_CD = 'A'
) PACTS
ON ABC.PKEY_SRC_OBJECT = PACTS.TEAM_ID;
对于前两个标志（ISMASTER 和 ISAGENT），我在不到 1 分钟的时间内得到结果，但对于最后一个标志（NUMPACTS），它运行几分钟而不提供任何结果。我觉得我的说法太沉重了，也许我应该换一种完全不同的方式。
我想你可能有一些复杂的事情。
您可以这样做（假设我已正确理解您的要求），如下所示：
WITH ttr AS (SELECT rltd_team_id,
COUNT(*) is_master
FROM team_team_rel
AND CODE = 'Double'
GROUP BY rltd_team_id),
trr AS (SELECT team_id,
COUNT(*) is_agent
FROM team_rol_rel
GROUP BY team_id)
pacts AS (SELECT trr1.team_id,
COUNT(*) num_pacts
FROM team_rol_rel trr1
INNER JOIN team_rol_pol_rel trpr ON (trr1.t_rol_rel_id = trpr.p_rol_rel_id)
INNER JOIN perso_pol_sta_rel ppsr ON (trpr.p_pol_id = ppsr.p_pol_id
WHERE trr1.rol_cd IN ('1', '2')
AND ppsr.st_cd = 'A'
GROUP BY trr1.team_id)
SELECT t.id pkey_src_object,
t.modf_dat update_date,
t.modf_usr updated_by,
p.first_nam first_name,
ttr.is_master,
trr.is_agent,
pacts.num_pacts
FROM team t
LEFT OUTER JOIN perso p ON t.id = p.team_id
LEFT OUTER JOIN ttr ON t.party_pty_id = ttr.rltd_team_id
LEFT OUTER JOIN trr ON t.party_pty_id = trr.team_id
LEFT OUTER JOIN pacts ON t.pkey_src_object = pacts.team_id;
NB 未经测试，因为您没有提供任何测试数据。
本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句