如何使用seaborn绘制成对的直方图

Here is a possible approach using seaborn's displots. Seaborn doesn't return the created graphical elements, but the ax can be interrogated. To make sure the ax only contains the elements you want upside down, those elements can be drawn first. Then, all the patches (the rectangular bars) and the lines (the curve for the kde) can be given their height in negative. Optionally the x-axis can be set at y == 0 using ax.spines['bottom'].set_position('zero').

import numpy as np
import matplotlib.pyplot as plt
import seaborn as sns

green = np.random.normal(20, 10, 1000)
blue = np.random.poisson(60, 1000)

fig, ax = plt.subplots(figsize=(8, 6))

sns.distplot(green, hist=True, kde=True, hist_kws={'edgecolor': 'black'}, kde_kws={'linewidth': 2}, bins=10,
             color='green')
for p in ax.patches:  # turn the histogram upside down
    p.set_height(-p.get_height())
for l in ax.lines:  # turn the kde curve upside down
    l.set_ydata(-l.get_ydata())

sns.distplot(blue, hist=True, kde=True, hist_kws={'edgecolor': 'black'}, kde_kws={'linewidth': 2}, bins=10,
             color='blue')
ax.set_xticks(np.arange(-20, 121, 20))
ax.set_yticks(np.arange(0.0, 0.07, 0.01))
ax.spines['top'].set_visible(False)
ax.spines['right'].set_visible(False)

pos_ticks = np.array([t for t in ax.get_yticks() if t > 0])
ticks = np.concatenate([-pos_ticks[::-1], [0], pos_ticks])
ax.set_yticks(ticks)
ax.set_yticklabels([f'{abs(t):.2f}' for t in ticks])
ax.spines['bottom'].set_position('zero')

plt.show()