需要基于其他字符串数组对数组对象进行排序并删除不匹配的对象
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
public class Test {
String name;
int no;
public String getName() {
return name;
}
public int getNo() {
return no;
}
public void setName(String name) {
this.name = name;
}
public void setNo(int no) {
this.no = no;
}
@Override
public String toString() {
return "Student{" +
"name='" + name + '\'' +
", no=" + no +
'}';
}
public static Test createStudent(String name, int no) {
Test student = new Test();
student.setName(name);
student.setNo(no);
return student;
}
public static void sortStudentInArrayList(List<String> scppriority) {
List<Test> students = new ArrayList<>();
Test student1 = createStudent("SCP1", 3);
students.add(student1);
Test student2 = createStudent("SCP2", 1);
students.add(student2);
Test student3 = createStudent("SCP3", 5);
students.add(student3);
Test student4 = createStudent("SCP4", 2);
students.add(student4);
//students.retainAll(scppriority);
System.out.println("Original students list: " + students);
Collections.sort(students, Comparator.comparing(s -> scppriority.indexOf(s.getName())));
}
public static void main(String[] args) {
List<String> string2 = new ArrayList<String>();
string2.add("SCP2");
string2.add("SCP3");
sortStudentInArrayList(string2);
}
}
<**输出原始学生列表：[学生{name ='SCP1'，否= 3}，学生{name ='SCP4'，否= 2}，学生{name ='SCP2'，否= 1}，学生{ name ='SCP3'，no = 5}]需要从学生列表中删除不匹配项，在此先感谢**>
试试这个，
List<Test> result = students.stream()
.filter(student -> scppriority.contains(student.getName()))
.sorted(Comparator.comparing(s -> scppriority.indexOf(s.getName())))
.collect(Collectors.toList());
System.out.println("Original students list: " + result);
输出：
Original students list: [Student{name='SCP2', no=1}, Student{name='SCP3', no=5}]
本文收集自互联网，转载请注明来源。
如有侵权，请联系 [email protected] 删除。
我来说两句