按顺序附加到 for 循环中的字典列表（Python 3）

用户7450368

我有一个奇怪的问题。我正在尝试创建一个引用生成器，它有一个引用部分的字典（每个值都是一个列表），从该列表中为每个键提取一个随机项目并将其附加到另一个列表中。然后将打印该列表以显示最终报价。

但是，我以随机顺序获取报价的部分。运行时，我得到这样的信息：

['avoid ', 'hobby.', "it's easy to ", 'your ', 'Occasionally ', 'most important ']

这是我的代码：

from random import choice

quoteWords = {
    "one": ["Sometimes ", "Often ", "Occasionally ", "Usually "],
    "two": ["it's best to ", "you should ", "you shouldn't ", "it's easy to ", "it's hard to "],
    "three": ["do ", "avoid ", "finish", "create ", "witness "],
    "four": ["the ", "a ", "your ", "society's ", "your friends' ", "the government's "],
    "five": ["best ", "most important ", "funniest "],
    "six": ["work.", "art.", "hobby.", "posessions."],
}

def inspire():
    quote = []
    counter = 0
    for key in quoteWords:
        quote.insert(counter, choice(quoteWords[key]))
        counter += 1
    return(quote)

print(inspire())

任何帮助将不胜感激。提前致谢！

schwobaseggl

您可以使用OrderedDict! 通常dict，不能保证keys' 或items' 顺序：

from collections import OrderedDict
quoteWords = OrderedDict([
    ("one", ["Sometimes ", "Often ", "Occasionally ", "Usually "]),
    ("two", ["it's best to ", "you should ", "you shouldn't ", "it's easy to ", "it's hard to "]),
    ("three", ["do ", "avoid ", "finish", "create ", "witness "]),
    ("four", ["the ", "a ", "your ", "society's ", "your friends' ", "the government's "]),
    ("five", ["best ", "most important ", "funniest "]),
    ("six", ["work.", "art.", "hobby.", "posessions."]),
])
# ...
print(''.join(inspire()))
Usually you should witness the best work.

您使用它的方式，您甚至不需要映射。您可以只使用列表列表并从每个列表中选择一个项目。

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