我不知道如何将文件表单服务发送到laravel控制器并将其存储在文件夹中。
这是视图和控制器(Angularjs前端)视图
<html>
<head>
<script src = "https://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script>
</head>
<body ng-app = "myApp">
<div ng-controller = "myCtrl">
<form enctype="multipart/form-data">
<input type = "file" file-model = "myFile"/>
<button ng-click = "uploadFile()">upload me</button>
</form>
</div>
** controller**
<script>
var myApp = angular.module('myApp', []);
myApp.directive('fileModel', ['$parse', function ($parse) {
return {
restrict: 'A',
link: function(scope, element, attrs) {
var model = $parse(attrs.fileModel);
var modelSetter = model.assign;
element.bind('change', function(){
scope.$apply(function(){
modelSetter(scope, element[0].files[0]);
});
});
}
};
}]);
myApp.service('fileUpload', ['$http', function ($http) {
this.uploadFileToUrl = function(file, uploadUrl){
var fd = {'file' : file}
var file = {
'file' : file
}
console.log(uploadUrl, fd)
$http.post("http://myipaddress/practice/upload/blog/public/index.php/uploadavtar",uploadUrl, fd)
.then(function(response) {
console.log(response.data)
});
}
}]);
myApp.controller('myCtrl', ['$scope', 'fileUpload', function($scope, fileUpload){
$scope.uploadFile = function(){
var file = $scope.myFile;
console.log('file is ' );
console.dir(file);
var uploadUrl = "/fileUpload";
fileUpload.uploadFileToUrl(file, uploadUrl);
};
}]);
</script>
Laravel控制器
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Http\Requests;
use Illuminate\Support\Facades\Input;
class UsersController extends Controller
{
public function uploadavtar(Request $request){
$extension = Input::file('file')->getClientOriginalExtension();
$filename = rand(11111111, 99999999). '.' . $extension;
Input::file('file')->move(
'192.168.2.68/practice/upload/public/files/uploads/', $filename
);
$fullPath = 'myipaddress/practice/upload' . $filename;
return $fullPath ;
}
}
我通过邮递员检查了上面的larave控制器,其正常工作的唯一问题是它没有存储文件。如果我从“提交”按钮执行相同操作,则显示错误
'Call to a member function getClientOriginalExtension() on a non-object
'
如何解决这两个问题。1.将文件形式服务发送到laravel控制器2.将其存储在定义的路径中。
我认为该错误提示请求(POST)中没有文件
if( $request->hasFile('file'))
{
$extension = Input::file('file')->getClientOriginalExtension();
$filename = rand(11111111, 99999999). '.' . $extension;
Input::file('file')->move('192.168.2.68/practice/upload/public/files/uploads/', $filename);
$fullPath = 'myipaddress/practice/upload' . $filename;
return $fullPath ;
}
else
{
//file from post does not exist
}
编辑
您的ajax参数错误
myApp.service('fileUpload', ['$http', function ($http) {
this.uploadFileToUrl = function(file, uploadUrl){
var fd = new FormData();
fd.append('file', file);
$http.post("http://myipaddress/practice/upload/blog/public/index.php/uploadavtar", fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined,'Process-Data': false}
})
.success(function(response){
console.log(response.data);
})
.error(function(){
console.log("error");
});
}
}]);
第一个参数用于链接,第二个是表单数据,最后一个是设置
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我来说两句