在自己的函数中自由编程

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct Mage{
    int power;
    char* name;
}typedef Mage;

void print(Mage* mage){
    printf("Mage: %s, Power: %i", mage->name, mage->power);
}

Mage create(char name[],int power){
    Mage* mage = malloc(sizeof(Mage));
    mage->power = power;
    mage->name = name;
    printf("New Mage!\n");
    return *mage;
}

void delete(Mage* mage){
    free(mage); // -> this is not working
    // how can I use free in an own function
    // I don't want to write free in main
}

int main() {

    Mage gandalf = create("Gandalf",50);
    print(&gandalf);
    delete(&gandalf);

    printf("\n\n\n");
    return 0;
}

我如何在自己的函数中使用free，我不想在main中编写free，此源代码包含free，此程序会崩溃

有人有主意吗？