发送列表指针到函数

对于我在C语言中进行的指针的练习，我想通过将指针listStart与要插入的结构一起发送到insertEntry函数，在链表的开头插入结构。但是，由于当前的代码，我无法执行此操作，因为listStart指针没有随其一起带它在主函数（列表的第一个结构）中指向的地址。

我知道我只是将指针本身复制到insertEntry函数中，因此它所指向的地址被忽略了。这意味着我在insertEntry函数中获得的listStart指针全部是空指针。

为了解决此问题，我尝试将listStart作为指针发送到insertEntry函数，但是，这只是给了我一个指向指向null的指针的指针。我试图将listStart的地址发送到该功能不起作用，因为它向该功能发送了null。

我的问题是：是否有可能这样做，而我只是错过了一些东西？还是不可能？

提前致谢。

// header to include standard input and output
#include <stdio.h>

struct entry
{
    int value;
    struct entry *next;
};


// prototype for insertEntry function
void insertEntry(struct entry *l, struct entry *i, struct entry *j);

int main(void)
{

    // declaration of array for linked list
    struct entry list1 = { 1 }, list2 = { 2 }, list3 = { 3 }, list4 = { 4 }, list5 = { 5 }, insert = { 8 }; 
    struct entry *listStart = &list1;

    // test to see if the value of the insert.value struct is correct
    printf("insert.value = %i\n", insert.value);


    // assign pointers in list.next to the next struct in the list to create a linked list
    list1.next = &list2;
    list2.next = &list3;
    list3.next = &list4;
    list4.next = &list5;
    list5.next = (struct entry *) 0;

    // print the linked list to make sure the pointers are going to the correct struct member
    printf("Original list!\n");
    while ( listStart != (struct entry *) 0 ) 
    {
        printf ("%i\n", listStart->value);
        listStart = listStart->next;
    }

    // send struct to change and struct to insert
    insertEntry(listStart, &insert, &list1);

    // restart the list from the beginning because in the last while loop the listStart was assigned to the null pointer.
    listStart  = &list1;

    // print the new list to show what has been inserted and moved around
    printf("New list!\n");
    while ( listStart != (struct entry *) 0 ) 
    {
        printf ("%i\n", listStart->value);
        listStart = listStart->next;
    }

    return 0;
}

// function to insert a new struct in the list and redirect an old struct in the list
void insertEntry(struct entry *l, struct entry *i, struct entry *j)
{
    i->next = l; // this is assigning the mem add of the pointer is list2.next to that of insert.next
    l = i; // this is assigning the mem add of i which would be insert.value to the pointer in list2.next

}