我正在使用Java编写一个简单的游戏。我正在使用一个开关，并希望重复使用在计算完成后获得的值，并再次显示菜单供用户选择，前提是用户再次选择了相同的选项。那就是存储先前的值，并用它代替初始值进行计算。当“ phystrength”变量等于0时，游戏结束。
这是我编写的代码的一部分：
导入java.util.Scanner; 公开课hw3 {
public static void main(String []args) {
class physician {
int phystrength;
int restoring;
String available;
}
physician med = new physician ();
med.phystrength=100;
med.restoring=30;
med.available="busy";
class surgeon {
int phystrength;
int restoring;
String available;
}
surgeon med1 = new surgeon ();
med1.phystrength=100;
med1.restoring=25;
med1.available="busy";
class nurses {
int phystrength;
int restoring;
String available;
}
nurses med2 = new nurses ();
med2.phystrength=90;
med2.restoring=20;
med2.available="busy";
class anesthesia {
int phystrength;
int restoring;
String available;
}
anesthesia med3 = new anesthesia ();
med3.phystrength=100;
med3.restoring=30;
med3.available="busy";
//Declaring variables
int strength, strength1,strength2=0 ;
int numsurgeons=3;
int numphysician= 3;
int numnurses=10;
int numanesthesia=2;
int remsurgeons,remphysician,remnurses,remanesthesia=0;
Scanner scan = new Scanner (System.in); //Creating a Scanner object to read use input
System.out.println("Welcome to National Cheng Kung University (NCKU) Hospital");
System.out.println();
System.out.println("Here is the list of current available medical staff at NCKU hospital");
System.out.println();
System.out.println("\nAvaialable personnel are (including their physical strength):"
+"\n\t 3 Surgeons -> " + med1.phystrength
+ "\n\t 3 Physicians -> " + med.phystrength
+"\n\t 10 Nurses -> " + med2.phystrength
+ "\n\t 2 anesthesiologists -> " + med3.phystrength);
System.out.println("Please enter the NUMBER of the type of medical treatment you are in need of");
String selec;
while (true) { //Allows user to continue to choose from the menu
System.out.println ("\nPlease choose from the menu below:"
+ "\n\t Medical Treatment-0"
+ "\n\t Dressing Wrap-1"
+ "\n\t Surgery-2"
+ "\n\t Chemotherapy-3"
+ "\n\t Emergency-Surgery-4"
+ "\n\t First Aid-5"
+ "\n\t End Program-6");
selec = scan.next();
switch (selec)
{
case "0":
System.out.println("You have chosen Medical Treatment (General)");
strength = med.phystrength-20;
strength1=med2.phystrength-10;
remphysician=numphysician-1;
remnurses=numnurses-1;
if (strength <100){
System.out.println("Physician is: " + med.available);
}
System.out.println("Physician's current Physical strength is:" + strength);
System.out.println("Nurse's current physical strength is:"+ strength1);
System.out.println("Number of remaining Physicians is " + remphysician +" and number of remaining nurses is " + remnurses);
break;
首先，这很糟糕，
class physician {
int phystrength;
int restoring;
String available;
}
class surgeon {
int phystrength;
int restoring;
String available;
}
这些是完全相同的对象，因此您不必创建新的类，而只创建new一个类的实例。
因此，只有其中之一。
class Medic {
public int phystrength, restoring;
boolean isAvailable; // true/false makes more sense than "busy" / "available"
public Medic (int strength, int restoring, boolean available) {
this.phystrength = strength;
this.restoring = restoring;
this.isAvailable = available;
}
}
还有很多。
Medic physician = new Medic(100, 30, false);
Medic surgeon = new Medic(100, 25, false);
// ... etc.
现在，就您的switch语句而言，请尝试扫描整数，因为这是您要提示的内容。
selec = scan.nextInt();
scan.nextLine(); // clear the newline
switch (selec) {
case 0: // Case on integers, instead
System.out.println("You have chosen Medical Treatment (General)");
而且，如果您要修改“人员”的状态，则实际上需要直接更改其状态，而不是存储单独的变量。
physician.phystrength -= 20;
nurse.phystrength -= 10; // "x -= y" --> "x = x - y"
remphysician=numphysician-1;
remnurses=numnurses-1;
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