我有一个查询，执行多个联接。我尝试只获取结果中最新的每个关键字的位置。
这是查询：
SELECT DISTINCT ON (p.keyword_id)
a.id AS account_id,
w.parent_id AS parent_id,
w.name AS name,
p.position AS position
FROM websites w
JOIN accounts a ON w.account_id = a.id
JOIN keywords k ON k.website_id = w.parent_id
JOIN positions p ON p.website_id = w.parent_id
WHERE a.amount > 0 AND w.parent_id NOTNULL AND (round((a.amount / a.payment_renewal_period), 2) BETWEEN 1 AND 19)
ORDER BY p.keyword_id, p.created_at DESC;
该查询的费用计划如下：
Unique (cost=73673.65..76630.38 rows=264 width=40) (actual time=30777.117..49143.023 rows=259 loops=1)
-> Sort (cost=73673.65..75152.02 rows=591347 width=40) (actual time=30777.116..47352.373 rows=10891486 loops=1)
Sort Key: p.keyword_id, p.created_at DESC
Sort Method: external merge Disk: 512672kB
-> Merge Join (cost=219.59..812.26 rows=591347 width=40) (actual time=3.487..3827.028 rows=10891486 loops=1)
Merge Cond: (w.parent_id = k.website_id)
-> Nested Loop (cost=128.46..597.73 rows=1268 width=44) (actual time=3.378..108.915 rows=61582 loops=1)
-> Nested Loop (cost=2.28..39.86 rows=1 width=28) (actual time=0.026..0.216 rows=7 loops=1)
-> Index Scan using index_websites_on_parent_id on websites w (cost=0.14..15.08 rows=4 width=28) (actual time=0.004..0.023 rows=7 loops=1)
Index Cond: (parent_id IS NOT NULL)
-> Bitmap Heap Scan on accounts a (cost=2.15..6.18 rows=1 width=4) (actual time=0.019..0.020 rows=1 loops=7)
Recheck Cond: (id = w.account_id)
Filter: ((amount > '0'::numeric) AND (round((amount / (payment_renewal_period)::numeric), 2) >= '1'::numeric) AND (round((amount / (payment_renewal_period)::numeric), 2) <= '19'::numeric))
Heap Blocks: exact=7
-> Bitmap Index Scan on accounts_pkey (cost=0.00..2.15 rows=1 width=0) (actual time=0.006..0.006 rows=1 loops=7)
Index Cond: (id = w.account_id)
-> Bitmap Heap Scan on positions p (cost=126.18..511.57 rows=4631 width=16) (actual time=0.994..8.226 rows=8797 loops=7)
Recheck Cond: (website_id = w.parent_id)
Heap Blocks: exact=1004
-> Bitmap Index Scan on index_positions_on_5_columns (cost=0.00..125.02 rows=4631 width=0) (actual time=0.965..0.965 rows=8797 loops=7)
Index Cond: (website_id = w.parent_id)
-> Sort (cost=18.26..18.92 rows=264 width=4) (actual time=0.106..1013.966 rows=10891487 loops=1)
Sort Key: k.website_id
Sort Method: quicksort Memory: 37kB
-> Seq Scan on keywords k (cost=0.00..7.64 rows=264 width=4) (actual time=0.005..0.039 rows=263 loops=1)
Planning time: 1.081 ms
Execution time: 49184.222 ms
问题是当我运行查询w.id而不是w.parent_id在联接位置时，总成本降低到
Unique (cost=3621.07..3804.99 rows=264 width=40) (actual time=128.430..139.550 rows=259 loops=1)
-> Sort (cost=3621.07..3713.03 rows=36784 width=40) (actual time=128.429..135.444 rows=40385 loops=1)
Sort Key: p.keyword_id, p.created_at DESC
Sort Method: external sort Disk: 2000kB
-> Merge Join (cost=128.73..831.59 rows=36784 width=40) (actual time=25.521..63.299 rows=40385 loops=1)
Merge Cond: (k.website_id = w.id)
-> Index Only Scan using index_keywords_on_website_id_deleted_at on keywords k (cost=0.27..24.23 rows=264 width=4) (actual time=0.137..0.274 rows=263 loops=1)
Heap Fetches: 156
-> Materialize (cost=128.46..606.85 rows=1268 width=44) (actual time=3.772..49.587 rows=72242 loops=1)
-> Nested Loop (cost=128.46..603.68 rows=1268 width=44) (actual time=3.769..30.530 rows=61582 loops=1)
-> Nested Loop (cost=2.28..45.80 rows=1 width=32) (actual time=0.047..0.204 rows=7 loops=1)
-> Index Scan using websites_pkey on websites w (cost=0.14..21.03 rows=4 width=32) (actual time=0.007..0.026 rows=7 loops=1)
Filter: (parent_id IS NOT NULL)
Rows Removed by Filter: 4
-> Bitmap Heap Scan on accounts a (cost=2.15..6.18 rows=1 width=4) (actual time=0.018..0.019 rows=1 loops=7)
Recheck Cond: (id = w.account_id)
Filter: ((amount > '0'::numeric) AND (round((amount / (payment_renewal_period)::numeric), 2) >= '1'::numeric) AND (round((amount / (payment_renewal_period)::numeric), 2) <= '19'::numeric))
Heap Blocks: exact=7
-> Bitmap Index Scan on accounts_pkey (cost=0.00..2.15 rows=1 width=0) (actual time=0.004..0.004 rows=1 loops=7)
Index Cond: (id = w.account_id)
-> Bitmap Heap Scan on positions p (cost=126.18..511.57 rows=4631 width=16) (actual time=0.930..2.341 rows=8797 loops=7)
Recheck Cond: (website_id = w.parent_id)
Heap Blocks: exact=1004
-> Bitmap Index Scan on index_positions_on_5_columns (cost=0.00..125.02 rows=4631 width=0) (actual time=0.906..0.906 rows=8797 loops=7)
Index Cond: (website_id = w.parent_id)
Planning time: 1.124 ms
Execution time: 157.167 ms
网站索引
Indexes:
"websites_pkey" PRIMARY KEY, btree (id)
"index_websites_on_account_id" btree (account_id)
"index_websites_on_deleted_at" btree (deleted_at)
"index_websites_on_domain_id" btree (domain_id)
"index_websites_on_parent_id" btree (parent_id)
"index_websites_on_processed_at" btree (processed_at)
职位指数
Indexes:
"positions_pkey" PRIMARY KEY, btree (id)
"index_positions_on_5_columns" UNIQUE, btree (website_id, keyword_id, created_at, engine_id, region_id)
"overlap_index" btree (keyword_id, created_at)
第二个EXPLAIN输出显示的行数减少了200倍以上，因此排序速度要快得多也就不足为奇了。
您会注意到，在两种情况下（Sort Method: external merge Disk: ...kB）排序都会溢出到磁盘上。如果你能保持在通过提高内存的排序work_mem，这将是多快。
但是第一种类型是如此之大，以至于您将无法将其放入内存中。
加快查询速度的想法：
对索引(keyword_id, created_at)进行positions。不确定是否有帮助。
首先进行过滤，如下所示：
SELECT
a.id AS account_id,
w.parent_id AS parent_id,
w.name AS name,
p.position AS position
FROM (SELECT DISTINCT ON (keyword_id)
positions,
website_id,
keyword_id,
created_at
FROM positions
ORDER BY keyword_id, created_at DESC) p
JOIN ...
WHERE ...
ORDER BY p.keyword_id, p.created_at DESC;
备注：该DISTINCT ON是有些奇怪，因为你不知道ORDER BY的值SELECT列表，这样的结果值没有明确定义。
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我来说两句